Find the area of the region in the first quadrant bounded above by y = √x + 2 and below by y = x. 543-2 5 -NWA C 3 2 1 街23. -2- 1 2 3 4 5

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the area of the region in the first quadrant bounded above by \( y = \sqrt{x} + 2 \) and below by \( y = x \).

**Detailed Explanation of Graph:**

The graph is a two-dimensional plot with \( x \)-axis and \( y \)-axis intersecting at the origin (0,0). The \( x \)-axis ranges from -5 to 5, and the \( y \)-axis ranges from -5 to 5.

The graph includes two curves:
1. The curve \( y = \sqrt{x} + 2 \) is shown in green.
2. The line \( y = x \) is also shown in green.

**Steps to Solve:**

1. **Identify Intersection Points:** 
   - Set the equations equal to find the points of intersection.
     \[
     \sqrt{x} + 2 = x
     \]
     Solve for \( x \):
     \[
     \sqrt{x} = x - 2
     \]
     Square both sides:
     \[
     x = (x - 2)^2 \\
     x = x^2 - 4x + 4
     \]
     Rearrange to form a quadratic equation:
     \[
     x^2 - 5x + 4 = 0
     \]
     Factor the quadratic:
     \[
     (x - 4)(x - 1) = 0
     \]
     Therefore, \( x = 1 \) and \( x = 4 \).

2. **Calculate the Area:**
   - The area is found by integrating the difference of the functions \( f(x) = \sqrt{x} + 2 \) and \( g(x) = x \) between the intersection points \( x = 1 \) and \( x = 4 \).
     \[
     \text{Area} = \int_{1}^{4} [ (\sqrt{x} + 2) - x ] \, dx
     \]
     Simplify the integrand:
     \[
     \text{Area} = \int_{1}^{4} (\sqrt{x} + 2 - x) \, dx
     \]
     Compute the integral:
     \[
     = \int_{1}^{4} \sqrt{x} \, dx + \int_{1}^{4}
Transcribed Image Text:**Problem Statement:** Find the area of the region in the first quadrant bounded above by \( y = \sqrt{x} + 2 \) and below by \( y = x \). **Detailed Explanation of Graph:** The graph is a two-dimensional plot with \( x \)-axis and \( y \)-axis intersecting at the origin (0,0). The \( x \)-axis ranges from -5 to 5, and the \( y \)-axis ranges from -5 to 5. The graph includes two curves: 1. The curve \( y = \sqrt{x} + 2 \) is shown in green. 2. The line \( y = x \) is also shown in green. **Steps to Solve:** 1. **Identify Intersection Points:** - Set the equations equal to find the points of intersection. \[ \sqrt{x} + 2 = x \] Solve for \( x \): \[ \sqrt{x} = x - 2 \] Square both sides: \[ x = (x - 2)^2 \\ x = x^2 - 4x + 4 \] Rearrange to form a quadratic equation: \[ x^2 - 5x + 4 = 0 \] Factor the quadratic: \[ (x - 4)(x - 1) = 0 \] Therefore, \( x = 1 \) and \( x = 4 \). 2. **Calculate the Area:** - The area is found by integrating the difference of the functions \( f(x) = \sqrt{x} + 2 \) and \( g(x) = x \) between the intersection points \( x = 1 \) and \( x = 4 \). \[ \text{Area} = \int_{1}^{4} [ (\sqrt{x} + 2) - x ] \, dx \] Simplify the integrand: \[ \text{Area} = \int_{1}^{4} (\sqrt{x} + 2 - x) \, dx \] Compute the integral: \[ = \int_{1}^{4} \sqrt{x} \, dx + \int_{1}^{4}
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