Find the area of the region bounded to the right by x = 4 - y and to the left by x = y. ܘ →NW+ 2₁ 543-2 1 2 3 4 5 -2- 3- 4- 5-

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Chapter1: Functions And Models
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## Finding the Area of a Region between Two Lines

### Problem Statement
Find the area of the region bounded to the right by \( x = 4 - y \) and to the left by \( x = y \).

### Explanation of the Graph

The accompanying graph is a Cartesian plane with the \( x \)-axis and \( y \)-axis clearly marked. Two intersecting lines are plotted to find the area of their bounded region:

1. **Line 1:** \( x = 4 - y \)
    - This line is indicated in green and has a negative slope. It intercepts the y-axis at (0, 4) and the x-axis at (4, 0).

2. **Line 2:** \( x = y \)
    - This line is represented in green and has a slope of 1. It passes through the origin (0, 0) and proceeds diagonally, intersecting both the positive x and y-axes at equal intervals.

Below are the key steps required to determine the area of the bounded region:
1. **Intersection Points:**
    - To find the intersections, set \( 4 - y = y \).
    - Solving the equation \( 4 = 2y \) yields \( y = 2 \).
    - Substitute \( y = 2 \) in \( x = y \) to get \( x = 2 \).
    - Hence, the intersection points are at (2, 2).

2. **Shaded Region:**
    - The shaded area on the graph (indicated via hatching) is bounded by the lines \( x = 4 - y \) and \( x = y \).

### Calculating the Area
Using integration, the area \( A \) can be calculated as follows:
\[ A = \int_{y=0}^{y=2} \left[(4 - y) - y \right] \, dy \]
\[ = \int_{y=0}^{y=2} (4 - 2y) \, dy \]
\[ = \left[4y - y^2\right]_{0}^{2} \]
\[ = \left[(4 \cdot 2 - 2^2) - (4 \cdot 0 - 0^2)\right] \]
\[ = \left[8 - 4\right] = 4 \]
Transcribed Image Text:## Finding the Area of a Region between Two Lines ### Problem Statement Find the area of the region bounded to the right by \( x = 4 - y \) and to the left by \( x = y \). ### Explanation of the Graph The accompanying graph is a Cartesian plane with the \( x \)-axis and \( y \)-axis clearly marked. Two intersecting lines are plotted to find the area of their bounded region: 1. **Line 1:** \( x = 4 - y \) - This line is indicated in green and has a negative slope. It intercepts the y-axis at (0, 4) and the x-axis at (4, 0). 2. **Line 2:** \( x = y \) - This line is represented in green and has a slope of 1. It passes through the origin (0, 0) and proceeds diagonally, intersecting both the positive x and y-axes at equal intervals. Below are the key steps required to determine the area of the bounded region: 1. **Intersection Points:** - To find the intersections, set \( 4 - y = y \). - Solving the equation \( 4 = 2y \) yields \( y = 2 \). - Substitute \( y = 2 \) in \( x = y \) to get \( x = 2 \). - Hence, the intersection points are at (2, 2). 2. **Shaded Region:** - The shaded area on the graph (indicated via hatching) is bounded by the lines \( x = 4 - y \) and \( x = y \). ### Calculating the Area Using integration, the area \( A \) can be calculated as follows: \[ A = \int_{y=0}^{y=2} \left[(4 - y) - y \right] \, dy \] \[ = \int_{y=0}^{y=2} (4 - 2y) \, dy \] \[ = \left[4y - y^2\right]_{0}^{2} \] \[ = \left[(4 \cdot 2 - 2^2) - (4 \cdot 0 - 0^2)\right] \] \[ = \left[8 - 4\right] = 4 \]
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