Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 6ECP: The resistance of a copper wire carrying an electrical current is directly proportional to its...
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Find the area of the circle. Use 3.15 (pi) and round your answer to the nearest hundredth
![### Calculating the Area of a Circle
To find the area of the circle, use the following formula:
\[ \text{Area} = \pi r^2 \]
where:
- \(\pi\) (pi) is a constant approximately equal to 3.14.
- \(r\) is the radius of the circle.
In this particular problem, the radius (\(r\)) is given as 14 meters.
So,
\[ \text{Area} = 3.14 \times (14)^2 \]
First, calculate \(14^2\):
\[ 14^2 = 196 \]
Then, multiply by \(\pi \):
\[ \text{Area} = 3.14 \times 196 \]
\[ \text{Area} = 615.44 \, \text{m}^2 \]
The final area of the circle is 615.44 square meters, rounded to the nearest hundredth.
**Diagram Explanation:**
- The diagram shows a circle.
- The radius of the circle, marked as \(r\), is 14 meters.
Fill in the final answer in the provided space on the educational website interface:
\[ \boxed{615.44 \, \text{m}^2} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcbb3e089-f921-4116-a585-798f4c3adb22%2Ff7d3fa2b-cb6a-45df-99c6-d9d965fcc7f2%2F8vvhsmk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Calculating the Area of a Circle
To find the area of the circle, use the following formula:
\[ \text{Area} = \pi r^2 \]
where:
- \(\pi\) (pi) is a constant approximately equal to 3.14.
- \(r\) is the radius of the circle.
In this particular problem, the radius (\(r\)) is given as 14 meters.
So,
\[ \text{Area} = 3.14 \times (14)^2 \]
First, calculate \(14^2\):
\[ 14^2 = 196 \]
Then, multiply by \(\pi \):
\[ \text{Area} = 3.14 \times 196 \]
\[ \text{Area} = 615.44 \, \text{m}^2 \]
The final area of the circle is 615.44 square meters, rounded to the nearest hundredth.
**Diagram Explanation:**
- The diagram shows a circle.
- The radius of the circle, marked as \(r\), is 14 meters.
Fill in the final answer in the provided space on the educational website interface:
\[ \boxed{615.44 \, \text{m}^2} \]
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