Find the area of a sector with a central angle of 160° and a dlameter of 8.6 cm. Round to the nearest tenth. O 7.6 cm2 O 25.8 cm2 O 103.3 cm2 O 3 cm?
Find the area of a sector with a central angle of 160° and a dlameter of 8.6 cm. Round to the nearest tenth. O 7.6 cm2 O 25.8 cm2 O 103.3 cm2 O 3 cm?
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
![**Question:**
Find the area of a sector with a central angle of 160° and a diameter of 8.6 cm. Round to the nearest tenth.
**Options:**
- ○ 7.6 cm²
- ○ 25.8 cm²
- ○ 103.3 cm²
- ○ 3 cm²
**Explanation:**
To find the area of a sector, you can use the formula:
\[ \text{Area of sector} = \left( \frac{\theta}{360} \right) \times \pi \times r^2 \]
Where:
- \(\theta\) is the central angle in degrees
- \(r\) is the radius of the circle
Given:
- Central angle (\(\theta\)) = 160°
- Diameter = 8.6 cm
First, calculate the radius \(r\):
\[ r = \frac{\text{diameter}}{2} = \frac{8.6}{2} = 4.3 \text{ cm} \]
Then plug these values into the formula:
\[ \text{Area of sector} = \left( \frac{160}{360} \right) \times \pi \times (4.3)^2 \]
Simplify the fraction:
\[ \left( \frac{160}{360} \right) = \left( \frac{4}{9} \right) \]
Now calculate:
\[ \text{Area of sector} = \left(\frac{4}{9}\right) \times \pi \times 18.49 \]
\[ \text{Area of sector} \approx \left(\frac{4}{9}\right) \times 3.1416 \times 18.49 \]
\[ \text{Area of sector} \approx \left(\frac{4}{9}\right) \times 58.09 \]
\[ \text{Area of sector} \approx 25.827 \text{ cm}^2 \]
Rounded to the nearest tenth:
\[ \text{Area of sector} \approx 25.8 \text{ cm}^2 \]
Therefore, the correct option is:
- ○ 25.8 cm²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe59874f9-f705-461a-94a3-07d771601ab4%2Ff707d2bb-b3f9-4c8b-8cd0-8086833ec528%2Fc0x0qks_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
Find the area of a sector with a central angle of 160° and a diameter of 8.6 cm. Round to the nearest tenth.
**Options:**
- ○ 7.6 cm²
- ○ 25.8 cm²
- ○ 103.3 cm²
- ○ 3 cm²
**Explanation:**
To find the area of a sector, you can use the formula:
\[ \text{Area of sector} = \left( \frac{\theta}{360} \right) \times \pi \times r^2 \]
Where:
- \(\theta\) is the central angle in degrees
- \(r\) is the radius of the circle
Given:
- Central angle (\(\theta\)) = 160°
- Diameter = 8.6 cm
First, calculate the radius \(r\):
\[ r = \frac{\text{diameter}}{2} = \frac{8.6}{2} = 4.3 \text{ cm} \]
Then plug these values into the formula:
\[ \text{Area of sector} = \left( \frac{160}{360} \right) \times \pi \times (4.3)^2 \]
Simplify the fraction:
\[ \left( \frac{160}{360} \right) = \left( \frac{4}{9} \right) \]
Now calculate:
\[ \text{Area of sector} = \left(\frac{4}{9}\right) \times \pi \times 18.49 \]
\[ \text{Area of sector} \approx \left(\frac{4}{9}\right) \times 3.1416 \times 18.49 \]
\[ \text{Area of sector} \approx \left(\frac{4}{9}\right) \times 58.09 \]
\[ \text{Area of sector} \approx 25.827 \text{ cm}^2 \]
Rounded to the nearest tenth:
\[ \text{Area of sector} \approx 25.8 \text{ cm}^2 \]
Therefore, the correct option is:
- ○ 25.8 cm²
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 1 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.Recommended textbooks for you

Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,

Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning

Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,

Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning