Find the area of a parallelogram PQRS, where P = (0, 0, 3), Q = (4,6,-4), R = (1, –4, −5) and S (5,2,-12).

Q: ABCD is a parallelogram. Find the point of intersection of the diagonals of this parallelogram and…

A:

Q: Find the cross product a × b where a = (0, 3, 4) and b = (5,1,2). axb =

A: Step 1: Step 2: Step 3: Step 4:

Q: 7x + 3y + 4z = 5, and 21x + 9y +12z = 13. %3D Neither

A: Given:7x+3y+4z=521x+9y+12z=13

Q: find the area of the parallelogram with vertices (2,4), (3, 8), (7, 12), and (8, 16). Answer:

A:

Q: U = 11. mi + 2루= (a) m

A:

Q: What is the area of parallelogram (-3,-4)    (-3,-9) (6,-2)     (6,-7) Square units?

A: The given points are: -3, -4-3, -96, -26, -7  To find the area of the parallelogram.

Q: Find the area of the parallelogram determined by v = (7, 0, 0) and w = (0,7, -3).

A: The step by step solution of the given problem is as follows:

Q: If P = (4,0) and Q = (3, 5), find the components of PQ PQ

A: Solution:-