Find the arc length of y = 4x/2 on 1 < x < 2.
Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 miles away.
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experiments to set up the devices.
Calculus II
![### Problem:
Find the arc length of \( y = 4x^{3/2} \) on \( 1 \leq x \leq 2 \).
### Explanation:
This problem requires finding the arc length of the function over the given interval. The arc length \( L \) of a curve defined by \( y = f(x) \) from \( x = a \) to \( x = b \) can be found using the following formula:
\[ L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx \]
For the function \( y = 4x^{3/2} \), the first derivative with respect to \( x \):
\[ \frac{dy}{dx} = 4 \cdot \frac{3}{2} x^{1/2} = 6x^{1/2} \]
Now, we substitute \( \frac{dy}{dx} \) into the arc length formula:
\[ L = \int_{1}^{2} \sqrt{1 + (6x^{1/2})^2} \, dx \]
\[ L = \int_{1}^{2} \sqrt{1 + 36x} \, dx \]
This integral can be solved to find the arc length of the curve from \( x = 1 \) to \( x = 2 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff003da25-8c7d-4491-8329-a317b002c309%2F87863d20-0c01-44f3-b6e5-a718bd6c3c89%2Ftz0zub_processed.png&w=3840&q=75)
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