Find the 50-th percentile of X. That is to say the value of x such that P (X ≤ x) = 0.5. b. Now say you have two independent jet engines. What is the probability that only one of them will last more than 12 months before needing to be rebuilt? c. Find the probability density function f(x) by taking the derivative of F(x) with respect to x.
Find the 50-th percentile of X. That is to say the value of x such that P (X ≤ x) = 0.5. b. Now say you have two independent jet engines. What is the probability that only one of them will last more than 12 months before needing to be rebuilt? c. Find the probability density function f(x) by taking the derivative of F(x) with respect to x.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
a. Find the 50-th percentile of X. That is to say the value of x such that P (X ≤ x) = 0.5.
b. Now say you have two independent jet engines. What is the probability that only one of them
will last more than 12 months before needing to be rebuilt?
will last more than 12 months before needing to be rebuilt?
c. Find the probability density function f(x) by taking the derivative of F(x) with respect to x.

Transcribed Image Text:4. Define the continuous random variable X as the time (in months) a jet engine can operate before
needing to be rebuilt. The cumulative distribution function F(x) (P(X ≤ x)) is given to be (note
this is the cumulative distribution function F(x), not the density function f(x)):
F(x) = P(X ≤ x) =
0
{:
1 — exp (-0.03x¹.2) = 1 – 6
-0.03x
1.2
x ≤ 0
0 < x <∞
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