Find the 40-th percentile for a normal random variable X ~ N(p = 55.9, σ = 7.4). The 40-th percentile for X is (Round the answer to 2 decimal places)
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A: μ=248.6σ=97.6n=246
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Q: A population of values has a normal distribution with μ=248.6�=248.6 and σ=97.6�=97.6. You intend to…
A: normal distribution μ = 248.6σ = 97.6n = 246P29 = ?
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- Let a be a random variable representing the percentage of protein content for early bloom alfalfa hay. The average percentage protein content of such early bloom alfalfa should be u = 17.2%. A farmer's co-op is thinking of buying a large amount of baled hay but suspects that the hay is from a later summer cutting with lower protein content. A small amount of hay was removed from each bale of a random sample of 50 bales. The average protein content from the samples was determined by a local agricultural college to be -15.8% with a sample standard deviation of S = 5.3%- At a = .05, does this hay have lower average protein content than the early bloom alfalfa?Gentle Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks, a veterinarian took the following glucose readings from this horse (in mg/100 ml). 91 88 80 103 97 110 86 89 The sample mean is x ≈ 93.0. Let x be a random variable representing glucose readings taken from Gentle Ben. We may assume that x has a normal distribution, and we know from past experience that ? = 12.5. The mean glucose level for horses should be ? = 85 mg/100 ml.† Do these data indicate that Gentle Ben has an overall average glucose level higher than 85? Use ? = 0.05. (a)What is the level of significance? State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? H0: ? > 85; H1: ? = 85; right-tailed H0: ? = 85; H1: ? < 85; left-tailed H0: ? = 85; H1: ? ≠ 85; two-tailed H0: ? = 85; H1: ? > 85; right-tailed (b)What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. The…Magnetic surveying is one technique used by archaeologists to determine anomalies arising from variations in magnetic susceptibility. Unusual changes in magnetic susceptibility might (or might not) indicate an important archaeological discovery. Let x be a random variable that represents a magnetic susceptibility (MS) reading for a randomly chosen site at an archaeological research location. A random sample of 120 sites gave the readings shown in the table below. Magnetic Susceptibility Readings, -6 centimeter-gram-second x 10 Magnetic (cmg x 10-6) Number of Estimated Susceptibility 0 5 and nq > 5 are both satisfied. Yes, it is appropriate since n 2 30. O Yes, it is appropriate since the criterian > 100 and np 5 and nq > 5 are not satisfied.
- Assume the random variable X is normally distributed, with mean μ=47 and standard deviation σ=8. Find the 14th percentile.Mark performed a two-sample z-test for proportions to test the hypothesis that there was no difference in the proportion who support increasing student fees between male and female students at a particular university. Mark obtained a z-statistic of 0. Based on this information, which of the following is always true. The sample proportions for male and females will be the same as the hypothesized proportions for male and female students at this university. The sample proportions for both male and female students at this university will be 0. All male and female students in the sample will feel the same way about supporting the increase in student fees. The sample proportions will be the same for both male and female students at this university. Test whether p1>p2 The sample data are x1=116,n1=258,x2=135,n2=311. Conduct a test at the α=0.10 level of significance. Determine the correct null and alternative hypothesis below. Determine the test statistic. Find the P-value: What is…Find the mean and standard deviation for each binomial random variable: a. n = 60, ππ = .65 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) Mean: Standard Deviation: b. n = 98, ππ = .45 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) Mean: Standard Deviation: ππ c. n = 50, = .70 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) Mean: Standard Deviation:
- Find the p-value for a two-tailed test, where z= -1.68the number of tickets purchased by an indivisual for beckham colleges holiday music festival is a uniformly distributed random variable ranging from 7 to 14. find the mean and standard deviation and round to the 2 decimal places.A sample of 100 clients of an exercise facility was selected. Let X = the number of days per week that a randomly selected client uses the exercise facility. Frequency 2 1 15 30 3 27 4 10 8 6. 8 Find the 80th percentile.
- The random variables X is the best described by a normal distribution with = 30 and a = 6. Find the z-score that corresponds to the following X values.:1. X = 212 X = 26.5stat 2bTotal blood volume (in ml) per body weight (in kg) is important in medical research. For healthy adults, the red blood cell volume mean is about u = 28 ml/kgt. Red blood cell volume that is too low or too high can indicate a medical problem. Suppose that Roger has had seven blood tests, and the red blood cell volumes were as follows. 31 26 43 37 32 38 29 Let x be a random variable that represents Roger's red blood cell volume. Assume that x has a normal distribution and o = 4.75. Do the data indicate that Roger's red blood cell volume is different (either way) from u = 28 ml/kg? Use a 0.01 level of significance. (a) What is the level of significance? State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? O Ho: H = 28 ml/kg; H,: µ > 28 ml/kg; right-tailed O Ho: H = 28 ml/kg; H,: u < 28 ml/kg; left-tailed O Họ: H + 28 ml/kg; H,: µ = 28 ml/kg; two-tailed O Ho: H = 28 ml/kg; H,: µ + 28 ml/kg; two-tailed (b) What sampling distribution will you…