Find the 3rd derivative using finite difference approach via the Taylor series Using Lagrangian interpolation formula find the value for for the set of points  and Using Lagrangian interpolation formula find the value of at  for the set of points , , and Given the data points and , construct the quadratic spline interpolation formula as we did class, and using the same constraining boundary condition Below is a table of and     -2 0 1 5 5 1 10 1.2 15 2   Set up the equations for a 3rd order Cubic spline ()   To be able to solve the system of equations, two more pieces of information are required. Note, for as the order of the polynomial approximation is increased the number of constraints/boundary conditions increase.  For quadratic spline we had on constraint, which for our in class example ).  For a cubic you will have two constraints, afor 4th order polynomial, you would have 4 constraints and so on.  Using arbitrary constraints like setting the third derivative in the  fourth point to zero may be used. However, the selection of a boundary condition, consisting of a pair of equations, is the commonly used method. The four conditions “natural spline”, “not-a-knot spline”, “periodic spline”, and “quadratic spline”.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 66E
icon
Related questions
Question

 

  1. Find the 3rd derivative using finite difference approach via the Taylor series

  2. Using Lagrangian interpolation formula find the value for for the set of points  and

  3. Using Lagrangian interpolation formula find the value of at  for the set of points , , and

  4. Given the data points and , construct the quadratic spline interpolation formula as we did class, and using the same constraining boundary condition

  5. Below is a table of and

   

-2

0

1

5

5

1

10

1.2

15

2

 

Set up the equations for a 3rd order Cubic spline ()

 

To be able to solve the system of equations, two more pieces of information are required. Note, for as the order of the polynomial approximation is increased the number of constraints/boundary conditions increase.  For quadratic spline we had on constraint, which for our in class example ).  For a cubic you will have two constraints, afor 4th order polynomial, you would have 4 constraints and so on.  Using arbitrary constraints like setting the third derivative in the  fourth point to zero may be used. However, the selection of a boundary condition, consisting of a pair of equations, is the commonly used method. The four conditions “natural spline”, “not-a-knot spline”, “periodic spline”, and “quadratic spline”. 

 

AI-Generated Solution
AI-generated content may present inaccurate or offensive content that does not represent bartleby’s views.
steps

Unlock instant AI solutions

Tap the button
to generate a solution

Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage