Find ·S= y dy 0(√3+2-5) (5√3+2-1+24)+C 0² (√y+2-5)(-5√/y+2+y+21)+C 03/(√3+2-5) (5√y+2+y+21) +C 03/(√3+2-5) (5√3+2+3+24)+C using the substitutionu +5=√√y+2 Vy+2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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y dy
Find
·S=
√y+2
© ²/(√√y+2−5) (5√/y+2¬y+24) + C
(√912-5)(-5√/91219121) 10
+C
3
0² (√y+2-5) (5√y+2+y+21)+C
03 (√x+2-5) (5√x+2+y+24) +€
+C
3
using the substitution u +5=√y+2.
Transcribed Image Text:y dy Find ·S= √y+2 © ²/(√√y+2−5) (5√/y+2¬y+24) + C (√912-5)(-5√/91219121) 10 +C 3 0² (√y+2-5) (5√y+2+y+21)+C 03 (√x+2-5) (5√x+2+y+24) +€ +C 3 using the substitution u +5=√y+2.
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