Find R, in the network above in order to achieve maximum power transfer. Take Vị = 8V, R1 = 12kN, R2 = 8KSN, R3 = 5kN and R4 = 5kN. RL = kN The open circuit voltage (with R, removed) is V. The power dissipated in the load resistor is Pr = mW.
Find R, in the network above in order to achieve maximum power transfer. Take Vị = 8V, R1 = 12kN, R2 = 8KSN, R3 = 5kN and R4 = 5kN. RL = kN The open circuit voltage (with R, removed) is V. The power dissipated in the load resistor is Pr = mW.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
![**Find \( R_L \) in the network above in order to achieve maximum power transfer.**
Take \( V_1 = 8 \, \text{V} \), \( R_1 = 12 \, \text{k}\Omega \), \( R_2 = 8 \, \text{k}\Omega \), \( R_3 = 5 \, \text{k}\Omega \), and \( R_4 = 5 \, \text{k}\Omega \).
- \( R_L = \) \(\_\_\_\) \( \text{k}\Omega \)
- The open circuit voltage (with \( R_L \) removed) is \(\_\_\_\) V.
- The power dissipated in the load resistor is \( P_L = \) \(\_\_\_\) mW.
**Explanation of Diagrams**
In this exercise, you are tasked with finding the load resistance \( R_L \) that will allow for maximum power transfer in the given network. The diagram itself isn't visible here, but we can infer from the problem description that there is a network with a voltage source \( V_1 \) and several resistors \( R_1, R_2, R_3, \text{and } R_4 \).
To solve for \( R_L \), recall that maximum power transfer occurs when \( R_L \) is equal to the Thevenin resistance of the circuit not including \( R_L \). You may need to calculate the open circuit voltage with \( R_L \) removed to determine the Thevenin equivalent voltage. Then, use these values to calculate the power dissipated in the load resistor.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0c42d3d3-c669-4ebd-a92e-b9a728000a05%2F7a085a4f-4a79-4dbe-9490-965c27e53a2b%2Fcznlehp_processed.png&w=3840&q=75)
Transcribed Image Text:**Find \( R_L \) in the network above in order to achieve maximum power transfer.**
Take \( V_1 = 8 \, \text{V} \), \( R_1 = 12 \, \text{k}\Omega \), \( R_2 = 8 \, \text{k}\Omega \), \( R_3 = 5 \, \text{k}\Omega \), and \( R_4 = 5 \, \text{k}\Omega \).
- \( R_L = \) \(\_\_\_\) \( \text{k}\Omega \)
- The open circuit voltage (with \( R_L \) removed) is \(\_\_\_\) V.
- The power dissipated in the load resistor is \( P_L = \) \(\_\_\_\) mW.
**Explanation of Diagrams**
In this exercise, you are tasked with finding the load resistance \( R_L \) that will allow for maximum power transfer in the given network. The diagram itself isn't visible here, but we can infer from the problem description that there is a network with a voltage source \( V_1 \) and several resistors \( R_1, R_2, R_3, \text{and } R_4 \).
To solve for \( R_L \), recall that maximum power transfer occurs when \( R_L \) is equal to the Thevenin resistance of the circuit not including \( R_L \). You may need to calculate the open circuit voltage with \( R_L \) removed to determine the Thevenin equivalent voltage. Then, use these values to calculate the power dissipated in the load resistor.
![This diagram depicts an electrical circuit containing a voltage source \( V_1 \) and five resistors labeled \( R_1, R_2, R_3, R_4, \) and \( R_L \).
- The circuit begins with the voltage source \( V_1 \) on the left side.
- \( R_1 \) is connected in series with the voltage source.
- Two branches are connected in parallel:
- The first branch contains resistor \( R_2 \).
- The second branch contains resistors \( R_3 \) and \( R_4 \) in series.
- \( R_3 \) and \( R_4 \) are connected in series with each other.
- Following these, the circuit continues in series to the load resistor \( R_L \) on the right side.
- The circuit then closes back to the voltage source \( V_1 \).
This type of circuit is known as a combination circuit, featuring both series and parallel components. Understanding how to simplify and analyze such circuits is essential in electrical engineering and physics to determine total resistance, voltage, and current.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0c42d3d3-c669-4ebd-a92e-b9a728000a05%2F7a085a4f-4a79-4dbe-9490-965c27e53a2b%2Fp6bk5cd_processed.png&w=3840&q=75)
Transcribed Image Text:This diagram depicts an electrical circuit containing a voltage source \( V_1 \) and five resistors labeled \( R_1, R_2, R_3, R_4, \) and \( R_L \).
- The circuit begins with the voltage source \( V_1 \) on the left side.
- \( R_1 \) is connected in series with the voltage source.
- Two branches are connected in parallel:
- The first branch contains resistor \( R_2 \).
- The second branch contains resistors \( R_3 \) and \( R_4 \) in series.
- \( R_3 \) and \( R_4 \) are connected in series with each other.
- Following these, the circuit continues in series to the load resistor \( R_L \) on the right side.
- The circuit then closes back to the voltage source \( V_1 \).
This type of circuit is known as a combination circuit, featuring both series and parallel components. Understanding how to simplify and analyze such circuits is essential in electrical engineering and physics to determine total resistance, voltage, and current.
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