Find P(z s 1.63). This probability corresponds to the area to the left of a point z = 1.63 standard deviations to the right of the mean
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![Find P(z < 1.63). This probability corresponds to the area to the left of a point
z = 1.63 standard deviations to the right of the mean](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e6efdb3-3686-4df4-83de-541f4b12b0d4%2F402ec42d-bf67-4050-b196-b7aa2ea8f5c0%2F3gg7h5o_processed.jpeg&w=3840&q=75)
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- Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100 and a standard deviation sigma equals 20 . Find the probability that a randomly selected adult has an IQ less than 95 a. Find the z-score: z = nothing (round to 2 decimal places) b. Find the probability: nothing (use 4 decimal places)Susan jogs to the park each day and the trip takes an average of µ = 22 minutes. The distribution of jog times is approximately normal with a standard deviation of σ = 10 minutes. For a randomly selected day, what is the probability that Susan’s jog to the park will take less than 16 minutes? Select one: a. 0.2743 b. 0.8957 c. 0.3236 d. 0.7554n=16 mean number of television per household is 4 with a standard deviation of 1 television. using chebychev's theorem, detemine at least how many households have between 2 and 6 television.
- Assume that adults have IQ scores that are normally distributed with a mean of 104.9 and a standard deviation of 16. Find the probability that a randomly selected adult has an IQ greater than 132.8. (Hint: Draw a graph.) The probability that a randomly selected adult from this group has an IQ greater than 132.8 is (Round to four decimal places as needed.)benk is 9.2 minutes with a standard deviation of The average waiting time for a drive in 2.6 minutes. Assume that the times A. Determine the probability, to 3 decimal places, t ustomer will have to wait less than 6 minutes. B. 20% of all customers will have to wait more than minutes. Round to 1 decimal place.Assume that the mean height of men in the United States is 70 inches, with a standard deviation of 3 inches. A particular man is 80 inches tall. Find the z-score of his height. (Round to two decimal places.)
- Suppose baby kittens' weights are normally distributed with a mean of 11.4 and a standard deviation of 2.1. The Z-score tells you how many units above the average (if Z-score is positive) or below the average (if Z- Score is negative) any particular baby kitten's weight is. Find the baby kitten weight that corresponds to the following Z-scores. Use the formula Z where u is the mean, o is the standard deviation, and X is the baby kitten weight. a. Z = = 0.07, X = b. Z = 1.63, X =Find the indicated probability and interpret the result. From 1975 through 2020, the mean annual gain of the Dow Jones Industrial Average was 651. A random sample of 32 years is selected from this population. What is the probability that the mean gain for the sample was between 400 and 700? Assume o = 1540. The probability is (Round to four decimal places as needed.)Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 89 and 121. Click to view page 1 of the table. Click to view page 2 of the table. Standard Normal Table (Page 2) The probability that a randomly selected adult has an IQ between 89 and 121 is (Type an integer or decimal rounded to four decimal places as needed.) POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 5478 .5517 .5557 .5596 ,5636 ,5675 .5714 .5753 0.2 .5793 .5832 5871 5910 .5948 .5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.5 .6915 6950 .6985 7019 .7054 .7088 7123 7157 .7190 .7224 0.6 .7257 .7291 7324 7357 7389 7422 7454 7486…
- Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 20. Find the probability that a randomly selected adult has an IQ less than 125. Click to view page 1 of the table. Click to view page 2 of the table. The probability that a randomly selected adult has an IQ less than 125 is. (Type an integer or decimal rounded to four decimal places as needed.) Enter vour answer in the answer box. 33283, xlsx Exit Honorlock 22 MacBook Air 吕0 F2 F4 F5 F10 %23 2$ % & * 3 5 7 8 E Y U D F J K C V B M %S4The average THC content of marijuana sold on the street is 9.4%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. a. What is the distribution of X? X - N( b. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 7.9. Round to 4 decimal places. c. Find the 65th percentile for this distribution. Round to 2 decimal places.For D only
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