Find parametric equations of the line that satisfies the stated conditions. The line through (– 8, 0, 8) that is parallel to the line x = 1 + 9t, y = 9 – t, z = 5 + 6t. O x = -8 – 9t, y = t, z = 8 – 6t O x = -8 + 9t, y = – 1, z = 8 + 6t O x = -8 + 9t, y = -t, z = 8 + 6t O x = - 9 – 8t, y = 1, z = – 6+ 8t O x = 9 – 8t, y = - 1, z = 6 + 8t

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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8Find parametric equations of the line that satisfies the stated conditions.
The line through (−8,0,8)(-8,0,8) that is parallel to the line x=1+9t, y=9−t, z=5+6t.

Find parametric equations of the line that satisfies the stated conditions.
The line through (– 8, 0, 8) that is parallel to the line x = 1 + 9t, y = 9 – t, z = 5 + 6t.
O x = -8 – 9t, y = t, z = 8 – 6t
O x = -8 + 9t, y = – 1, z = 8 + 6t
O x = -8 + 9t, y = -t, z = 8 + 6t
O x = - 9 – 8t, y = 1, z = – 6+ 8t
O x = 9 – 8t, y = - 1, z = 6 + 8t
Transcribed Image Text:Find parametric equations of the line that satisfies the stated conditions. The line through (– 8, 0, 8) that is parallel to the line x = 1 + 9t, y = 9 – t, z = 5 + 6t. O x = -8 – 9t, y = t, z = 8 – 6t O x = -8 + 9t, y = – 1, z = 8 + 6t O x = -8 + 9t, y = -t, z = 8 + 6t O x = - 9 – 8t, y = 1, z = – 6+ 8t O x = 9 – 8t, y = - 1, z = 6 + 8t
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