I’m so confused on how to do this. **Title: Calculating the Measure of an Angle in a Diagram****Problem Statement:**Find \( m\angle Q \) for the diagram in degrees.**Diagram Explanation:**The diagram is a triangle \( \triangle PQR \) with an external line segment \( \overline{RV} \). The known angles in the diagram are:- \( \angle VRP = 147^\circ \)- \( \angle QPR = 75^\circ \)The task is to determine the measure of the angle \( \angle Q \).**Solution:**In \( \triangle PQR \), the sum of the internal angles is always \( 180^\circ \). We can use the following equation:1. Sum of internal angles: \[ \angle P + \angle Q + \angle R = 180^\circ \]2. We know: \[ \angle P = 75^\circ \] \[ \angle VRP = 147^\circ \quad (\text{external angle to } \angle R) \]3. Using the external angle theorem: \[ \angle VRP = \angle Q + \angle P \] \[ 147^\circ = \angle Q + 75^\circ \]4. Solving for \( \angle Q \): \[ \angle Q = 147^\circ - 75^\circ = 72^\circ \]**Final Answer:**\( m\angle Q = 72^\circ \)**Submit your work using the form:**- **Answer:** [Input Box]- Click [Submit Answer] to check your response.

Name: I’m so confused on how to do this. **Title: Calculating the Measure of
Uploaded: 2024-03-20T07:06:27.000Z
Channel: Bartleby
Description: I’m so confused on how to do this. **Title: Calculating the Measure of an Angle in a Diagram****Problem Statement:**Find \( m\angle Q \) for the diagram in degrees.**Diagram Explanation:**The diagram is a triangle \( \triangle PQR \) with an external