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Find lim Ax-0 f(x+1 + Ax) = f(x) - Ax f(x) = 3x². - 9x Step 1 Find f(x + Ax) by substituting x + Ax in place of x in f(x) = 3x² - 9x. f(x + Ax) = 3(x + Ax - 9(x + Ax Step 2 Simplify the above equation. f(x + Ax) = 3x² +6 x+Ax +34x² - 9x 9 x + Ax 4x

Find lim Ax-0 f(x+1 + Ax) = f(x) - Ax f(x) = 3x². - 9x Step 1 Find f(x + Ax) by substituting x + Ax in place of x in f(x) = 3x² - 9x. f(x + Ax) = 3(x + Ax - 9(x + Ax Step 2 Simplify the above equation. f(x + Ax) = 3x² +6 x+Ax +34x² - 9x 9 x + Ax 4x

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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On step 2, the steps shows a 6. Where did the 6 come from? When I factor it out, I don't see how a 6 would populate.

Find lim Ax- 0 f(x + Ax) = f(x) Ax f(x) = 3x² Step 1 Find f(x + Ax) by substituting x + Ax in place of x in f(x) = 3x² - 9x. 9(x + Ax f(x + Ax) 9x = 3(x + Ax Step 2 Simplify the above equation. f(x + Ax) = 3x² +6 Submit Skip (you cannot come back) x+Ax X +34x²9x9 x + Ax Ax
Transcribed Image Text:Find lim Ax- 0 f(x + Ax) = f(x) Ax f(x) = 3x² Step 1 Find f(x + Ax) by substituting x + Ax in place of x in f(x) = 3x² - 9x. 9(x + Ax f(x + Ax) 9x = 3(x + Ax Step 2 Simplify the above equation. f(x + Ax) = 3x² +6 Submit Skip (you cannot come back) x+Ax X +34x²9x9 x + Ax Ax
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