Find f'(x). f(x) = et 5x2 + 2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem Statement

**Objective:** Find the derivative \( f'(x) \) of the given function.

**Function Definition:**

\[ f(x) = \frac{e^x}{5x^2 + 2} \]

### Explanation

To solve for \( f'(x) \), you'll need to apply the quotient rule for differentiation, which is used when finding the derivative of a division of two functions. The formula for the quotient rule is:

\[
\left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2}
\]

Where:
- \( u = e^x \) and \( u' = \frac{d}{dx}(e^x) = e^x \)
- \( v = 5x^2 + 2 \) and \( v' = \frac{d}{dx}(5x^2 + 2) = 10x \)

### Solution Steps

1. **Apply the Quotient Rule:**

\[
f'(x) = \frac{e^x(5x^2 + 2) - e^x \cdot 10x}{(5x^2 + 2)^2}
\]

2. **Simplify the Expression:**

Now, calculate the expression in the numerator:

\[
f'(x) = \frac{e^x(5x^2 + 2 - 10x)}{(5x^2 + 2)^2}
\]

3. **Further Simplification:**

The result can be further simplified within the brackets:

\[
5x^2 + 2 - 10x = 5x^2 - 10x + 2
\]

Thus, the derivative \( f'(x) \) becomes:

\[
f'(x) = \frac{e^x (5x^2 - 10x + 2)}{(5x^2 + 2)^2}
\]

The derivative \( f'(x) \) gives the rate of change of the function \( f(x) \) with respect to \( x \), using quotient rule differentiation.

### Conclusion

This problem effectively utilizes the quotient rule of differentiation, an important concept in calculus for calculating derivatives of functions involving division.
Transcribed Image Text:### Problem Statement **Objective:** Find the derivative \( f'(x) \) of the given function. **Function Definition:** \[ f(x) = \frac{e^x}{5x^2 + 2} \] ### Explanation To solve for \( f'(x) \), you'll need to apply the quotient rule for differentiation, which is used when finding the derivative of a division of two functions. The formula for the quotient rule is: \[ \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \] Where: - \( u = e^x \) and \( u' = \frac{d}{dx}(e^x) = e^x \) - \( v = 5x^2 + 2 \) and \( v' = \frac{d}{dx}(5x^2 + 2) = 10x \) ### Solution Steps 1. **Apply the Quotient Rule:** \[ f'(x) = \frac{e^x(5x^2 + 2) - e^x \cdot 10x}{(5x^2 + 2)^2} \] 2. **Simplify the Expression:** Now, calculate the expression in the numerator: \[ f'(x) = \frac{e^x(5x^2 + 2 - 10x)}{(5x^2 + 2)^2} \] 3. **Further Simplification:** The result can be further simplified within the brackets: \[ 5x^2 + 2 - 10x = 5x^2 - 10x + 2 \] Thus, the derivative \( f'(x) \) becomes: \[ f'(x) = \frac{e^x (5x^2 - 10x + 2)}{(5x^2 + 2)^2} \] The derivative \( f'(x) \) gives the rate of change of the function \( f(x) \) with respect to \( x \), using quotient rule differentiation. ### Conclusion This problem effectively utilizes the quotient rule of differentiation, an important concept in calculus for calculating derivatives of functions involving division.
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