Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![### Problem Statement
**Objective:** Find the derivative \( f'(x) \) of the given function.
**Function Definition:**
\[ f(x) = \frac{e^x}{5x^2 + 2} \]
### Explanation
To solve for \( f'(x) \), you'll need to apply the quotient rule for differentiation, which is used when finding the derivative of a division of two functions. The formula for the quotient rule is:
\[
\left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2}
\]
Where:
- \( u = e^x \) and \( u' = \frac{d}{dx}(e^x) = e^x \)
- \( v = 5x^2 + 2 \) and \( v' = \frac{d}{dx}(5x^2 + 2) = 10x \)
### Solution Steps
1. **Apply the Quotient Rule:**
\[
f'(x) = \frac{e^x(5x^2 + 2) - e^x \cdot 10x}{(5x^2 + 2)^2}
\]
2. **Simplify the Expression:**
Now, calculate the expression in the numerator:
\[
f'(x) = \frac{e^x(5x^2 + 2 - 10x)}{(5x^2 + 2)^2}
\]
3. **Further Simplification:**
The result can be further simplified within the brackets:
\[
5x^2 + 2 - 10x = 5x^2 - 10x + 2
\]
Thus, the derivative \( f'(x) \) becomes:
\[
f'(x) = \frac{e^x (5x^2 - 10x + 2)}{(5x^2 + 2)^2}
\]
The derivative \( f'(x) \) gives the rate of change of the function \( f(x) \) with respect to \( x \), using quotient rule differentiation.
### Conclusion
This problem effectively utilizes the quotient rule of differentiation, an important concept in calculus for calculating derivatives of functions involving division.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19e290b3-c32d-41c1-939c-80705e447f02%2Fb69a2735-0938-43dd-a07d-0538b7afae0f%2F0qiebf5_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement
**Objective:** Find the derivative \( f'(x) \) of the given function.
**Function Definition:**
\[ f(x) = \frac{e^x}{5x^2 + 2} \]
### Explanation
To solve for \( f'(x) \), you'll need to apply the quotient rule for differentiation, which is used when finding the derivative of a division of two functions. The formula for the quotient rule is:
\[
\left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2}
\]
Where:
- \( u = e^x \) and \( u' = \frac{d}{dx}(e^x) = e^x \)
- \( v = 5x^2 + 2 \) and \( v' = \frac{d}{dx}(5x^2 + 2) = 10x \)
### Solution Steps
1. **Apply the Quotient Rule:**
\[
f'(x) = \frac{e^x(5x^2 + 2) - e^x \cdot 10x}{(5x^2 + 2)^2}
\]
2. **Simplify the Expression:**
Now, calculate the expression in the numerator:
\[
f'(x) = \frac{e^x(5x^2 + 2 - 10x)}{(5x^2 + 2)^2}
\]
3. **Further Simplification:**
The result can be further simplified within the brackets:
\[
5x^2 + 2 - 10x = 5x^2 - 10x + 2
\]
Thus, the derivative \( f'(x) \) becomes:
\[
f'(x) = \frac{e^x (5x^2 - 10x + 2)}{(5x^2 + 2)^2}
\]
The derivative \( f'(x) \) gives the rate of change of the function \( f(x) \) with respect to \( x \), using quotient rule differentiation.
### Conclusion
This problem effectively utilizes the quotient rule of differentiation, an important concept in calculus for calculating derivatives of functions involving division.
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