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Find f(x + Ax) by substituting x + Ax in place of x in f(x) = 9x² - 5x. f(x + Ax) = 9( x+ Ax D² - 5( x + Ar x +Ax x + Ar Step 2 Simplify the above equation. f(x + Ax) = 9x² + 18 xAx + 9AX2 – 5x - X Ax

Find f(x + Ax) by substituting x + Ax in place of x in f(x) = 9x² - 5x. f(x + Ax) = 9( x+ Ax D² - 5( x + Ar x +Ax x + Ar Step 2 Simplify the above equation. f(x + Ax) = 9x² + 18 xAx + 9AX2 – 5x - X Ax

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find f(x + Ax) by substituting x + Ax in place of x in f(x) = 9x - 5x. 2 f(x + Ax) = 9( x+Ax x + Ax D² – 5( x + Ax x + Ar Step 2 Simplify the above equation. f(x + Ax) = 9x² + 18 xAx + 9Ax2 – 5x – X Ax
Transcribed Image Text:Find f(x + Ax) by substituting x + Ax in place of x in f(x) = 9x - 5x. 2 f(x + Ax) = 9( x+Ax x + Ax D² – 5( x + Ax x + Ar Step 2 Simplify the above equation. f(x + Ax) = 9x² + 18 xAx + 9Ax2 – 5x – X Ax
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