Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Title: Calculating the Derivative of a Rational Function**
**Objective:**
- Find the derivative \( f'(x) \) for the given function
- Evaluate \( f'(x) \) at the specified point
**Given Function:**
\[ g(x) = \frac{5}{x - 3} \]
**Task:**
- Compute the derivative \( g'(x) \)
- Evaluate \( g'(x) \) at \( x = 4 \)
**Instructions:**
1. **Identify the Type of Function:**
- This is a rational function, specifically of the form \( \frac{c}{x - a} \).
2. **Apply the Derivative Rule for Rational Functions:**
- Recall that the derivative of \( \frac{c}{x} \) is \( -\frac{c}{x^2} \).
- Use the chain rule if necessary for specific transformations of the denominator.
3. **Calculation Steps:**
a. **Find the Derivative \( g'(x) \):**
- First, express \( g(x) \) in terms of a negative exponent:
\[ g(x) = 5(x - 3)^{-1} \]
- Differentiate using the power rule and chain rule:
\[ g'(x) = -5(x - 3)^{-2} \cdot 1 \]
\[ g'(x) = -\frac{5}{(x - 3)^2} \]
b. **Evaluate \( g'(4) \):**
- Substitute \( x = 4 \) into \( g'(x) \):
\[ g'(4) = -\frac{5}{(4 - 3)^2} \]
\[ g'(4) = -\frac{5}{1} \]
\[ g'(4) = -5 \]
**Conclusion:**
The derivative \( g'(x) \) is \( -\frac{5}{(x - 3)^2} \) and the value of the derivative at \( x = 4 \) is \( -5 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd91f179b-a569-4e75-8153-e53e6ddce2b6%2Fafe2da26-04de-47ce-8709-b106a13b3fd2%2Fqxxi5cr.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Calculating the Derivative of a Rational Function**
**Objective:**
- Find the derivative \( f'(x) \) for the given function
- Evaluate \( f'(x) \) at the specified point
**Given Function:**
\[ g(x) = \frac{5}{x - 3} \]
**Task:**
- Compute the derivative \( g'(x) \)
- Evaluate \( g'(x) \) at \( x = 4 \)
**Instructions:**
1. **Identify the Type of Function:**
- This is a rational function, specifically of the form \( \frac{c}{x - a} \).
2. **Apply the Derivative Rule for Rational Functions:**
- Recall that the derivative of \( \frac{c}{x} \) is \( -\frac{c}{x^2} \).
- Use the chain rule if necessary for specific transformations of the denominator.
3. **Calculation Steps:**
a. **Find the Derivative \( g'(x) \):**
- First, express \( g(x) \) in terms of a negative exponent:
\[ g(x) = 5(x - 3)^{-1} \]
- Differentiate using the power rule and chain rule:
\[ g'(x) = -5(x - 3)^{-2} \cdot 1 \]
\[ g'(x) = -\frac{5}{(x - 3)^2} \]
b. **Evaluate \( g'(4) \):**
- Substitute \( x = 4 \) into \( g'(x) \):
\[ g'(4) = -\frac{5}{(4 - 3)^2} \]
\[ g'(4) = -\frac{5}{1} \]
\[ g'(4) = -5 \]
**Conclusion:**
The derivative \( g'(x) \) is \( -\frac{5}{(x - 3)^2} \) and the value of the derivative at \( x = 4 \) is \( -5 \).
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