Find f'(a). f(x) = 2x2 – 5x + 2 f'(a) =

Q: S)-(4r' -2r² +3x)(A+--3) Find f"(x).

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Q: Find f f ''(x) = 8 + 6x + 36x2, f(0) = 2, f (1) = 13

A: *to find:- f(x).

Q: f(x) = (6x – 4)* - (4x² + 5)³. f'(x) =

A: Using product rule and chain rule of derivative,

Q: f'(x) = -2x

A:

Q: Find(f ^−1)'(a).f(x) = 4x^3 + 4x^2 + 7x + 2, a = 2(f ^−1)'(a) =

A: Here a function f(x) is given and value of a is given we need to find the derivative of inverse of…

Q: Find f'(x). f(x) = 2 In (2+7x2)

A: Taking derivative with respect to x,   Take the constant 2 out of the brackets,

Q: find f'(x) for f(x)= x2-x-20/ x+4

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Q: Find f'(x)

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Q: f(x)= 3*+log2* Find f'(x)

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Q: Find  f'(a)

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Q: Find f'(x). 9 f(x) = x2 + 3x +

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Q: Find f'(x). f(x) = − 5 In x + 11x² - 10 f'(x) =

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Q: Find f'(x). f(x) = 9x³ (x² − 9) f'(x) =

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Q: Find f'(x) for f(x) = (x2 + 2)3

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Q: Find f'(x) and f''(x). 2 x - 5x x+1 f(x)=

A: Given: f(x)=x2-5xx+1

Q: Find f'(a). f'(a) = f(x) = 2x² - 3x + 1

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Q: f(x) = x2 + 2x + ( 9 divided by x) a.) Find f '(x).

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Q: Find f’(a) F(x)=3x^2 - 5x +4

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Q: find f'(x) given that f(x) = (2x5+2x2-3) (3x3-2x2 + 4)

A: The function f(x)=2x5+2x2-33x3-2x2+4, we have to find f'(x).

Q: Find f'(a). f'(a) = f(x) = √2 - 6x -3 2-6 X

A:

Q: Find f'(x) for the function. f(x) = 8x3 - x + 1 f'(x) =

A: Given f(x) = 8x3-x+1 We know that d(xn)/dx = n•xn-1

Q: Find f'(16) if f(x) = 7x² + 3x +3 √I

A: To find the derivative of given function

Q: Find f'(9) if f(x) = 7x² +6x + 2 √x f'(9)=

A: we know, ddx(xn)=nx(n-1) for any real n

Q: f"(x) = 3x + 6 and f'(-2) = -2 and f(-2) = 2. Find f'(x) = and find f(3) =

A: We can solve this using application of integral.

Q: Find f'(a) for x2 f(x) = x + 6 at a = 3.

A: Given function :

Q: f(x)=x3-2

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Q: Find f'(a). f(x) = 3x 3x + 2 3x² f'(a) =

A: