Find f '(x) of f (x) =/ 2x3 – x2 – 4x – 5. 6x2 – 2x (A 2 V 2x3 - x2 - 4x – 5 (3x + 2) (x– 1) 2 V 2x3 – x2 – 4x (3x + 2) (x- 1) C 2x3 – x² – 4x 5 (зк- 2) (2х + 2) D 2x³ – x² – 4x – 5

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find f '(x) of ƒ (x) =/2x3 – x² – 4x – 5.
6x2
2x
(A
2 V 2x3 - x2 – 4x – 5
(3x+ 2) (x- 1)
B
2 / 2r3 - x2 – 4x – 5
(3x+2) (x- 1)
/2x³ – x² – 4x – 5
4х — 5
(зи - 2) (2x + 2)
2x³ – x² – 4x - 5
Transcribed Image Text:Find f '(x) of ƒ (x) =/2x3 – x² – 4x – 5. 6x2 2x (A 2 V 2x3 - x2 – 4x – 5 (3x+ 2) (x- 1) B 2 / 2r3 - x2 – 4x – 5 (3x+2) (x- 1) /2x³ – x² – 4x – 5 4х — 5 (зи - 2) (2x + 2) 2x³ – x² – 4x - 5
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