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Find f '(a). 5t + 11 f(t) t + 8 Step 1 To find f '(a), we will use the formula = lim t) – f(a) f '(a) 5t + 11 Since f(t) we have t + 8 5t + 11 5a + 11 f '(a) lim t + 8 a + 8 %D Putting the fractions in the numerator over a common denominator and simplifying, we have || (5t + 11) (5a + 11)(t + 8) 5t + 11 5a + 11 t + 8 a + 8 (t + 8)(a + 8) 5ta + 11a + 40t + 88 – 5at (t + 8)(a + 8) - 11t – 40a – 88 )e-( la (t + 8)(a + 8)

Find f '(a). 5t + 11 f(t) t + 8 Step 1 To find f '(a), we will use the formula = lim t) – f(a) f '(a) 5t + 11 Since f(t) we have t + 8 5t + 11 5a + 11 f '(a) lim t + 8 a + 8 %D Putting the fractions in the numerator over a common denominator and simplifying, we have || (5t + 11) (5a + 11)(t + 8) 5t + 11 5a + 11 t + 8 a + 8 (t + 8)(a + 8) 5ta + 11a + 40t + 88 – 5at (t + 8)(a + 8) - 11t – 40a – 88 )e-( la (t + 8)(a + 8)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find f '(a). 5t + 11 f(t) t + 8 Step 1 To find f '(a), we will use the formula = lim t) – f(a) f '(a) 5t + 11 Since f(t) we have t + 8 5t + 11 5a + 11 f '(a) lim t + 8 a + 8 %D Putting the fractions in the numerator over a common denominator and simplifying, we have || (5t + 11) (5a + 11)(t + 8) 5t + 11 5a + 11 t + 8 a + 8 (t + 8)(a + 8) 5ta + 11a + 40t + 88 – 5at (t + 8)(a + 8) - 11t – 40a – 88 )e-( la (t + 8)(a + 8)
Transcribed Image Text:Find f '(a). 5t + 11 f(t) t + 8 Step 1 To find f '(a), we will use the formula = lim t) – f(a) f '(a) 5t + 11 Since f(t) we have t + 8 5t + 11 5a + 11 f '(a) lim t + 8 a + 8 %D Putting the fractions in the numerator over a common denominator and simplifying, we have || (5t + 11) (5a + 11)(t + 8) 5t + 11 5a + 11 t + 8 a + 8 (t + 8)(a + 8) 5ta + 11a + 40t + 88 – 5at (t + 8)(a + 8) - 11t – 40a – 88 )e-( la (t + 8)(a + 8)
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