Find f '(a). 3t + 9 f(t) : t + 4 %3D Step 1 To find f'(a), we will use the formula f '(a) = lim t) – f(a) t - a Since f(t) 3t + 9 we have %3D t + 4 3t +9 t + 4 t - a За + 9 f '(a) = lim a + 4 . Putting the fractions in the numerator over a common denominator and simplifying, we have 3t + 9 За + 9 (3t + - (3a + 9)(t + 4) %3D t + 4 a + 4 (t + 4)(a + 4) 3ta + 9a + 12t + 36 - 3at - 9t - 12a - 36 (t + 4)(a + 4) %3D (t + 4)(a + 4)
Find f '(a). 3t + 9 f(t) : t + 4 %3D Step 1 To find f'(a), we will use the formula f '(a) = lim t) – f(a) t - a Since f(t) 3t + 9 we have %3D t + 4 3t +9 t + 4 t - a За + 9 f '(a) = lim a + 4 . Putting the fractions in the numerator over a common denominator and simplifying, we have 3t + 9 За + 9 (3t + - (3a + 9)(t + 4) %3D t + 4 a + 4 (t + 4)(a + 4) 3ta + 9a + 12t + 36 - 3at - 9t - 12a - 36 (t + 4)(a + 4) %3D (t + 4)(a + 4)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![Find f '(a).
f(t) =
3t + 9
t + 4
Step 1
To find f '(a), we will use the formula
f '(a) = lim f(t) – f(a)
t a
t - a
Since f(t)=
3t + 9
%3D
we have
t + 4
За + 9
a + 4.
t - a
3t + 9
f '(a) = lim
t a
%3D
t + 4
Putting the fractions in the numerator over a common denominator and simplifying, we have
)-
3t + 9
За + 9
(3t + 9)
(За + 9)(t + 4)
t + 4
a + 4
(t + 4)(a + 4)
3ta + 9a + 12t + 36 – 3at - 9t - 12a - 36
(t + 4)(a + 4)
9t 12a 36
(t + 4)(a + 4)
II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fce02bb84-762a-4ccc-9fbc-69fff564b031%2F0fc5e439-d11c-497a-b5fb-ee5d28566766%2Fo492g5p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find f '(a).
f(t) =
3t + 9
t + 4
Step 1
To find f '(a), we will use the formula
f '(a) = lim f(t) – f(a)
t a
t - a
Since f(t)=
3t + 9
%3D
we have
t + 4
За + 9
a + 4.
t - a
3t + 9
f '(a) = lim
t a
%3D
t + 4
Putting the fractions in the numerator over a common denominator and simplifying, we have
)-
3t + 9
За + 9
(3t + 9)
(За + 9)(t + 4)
t + 4
a + 4
(t + 4)(a + 4)
3ta + 9a + 12t + 36 – 3at - 9t - 12a - 36
(t + 4)(a + 4)
9t 12a 36
(t + 4)(a + 4)
II
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