Find e for A = 1 -1 1 2 34 002

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
Question
### Problem Statement

**2. Find \( e^A \) for** 

\[ 
A = \begin{bmatrix} 
1 & 1 & 2 \\ 
-1 & 3 & 4 \\ 
0 & 0 & 2 
\end{bmatrix} 
\]

### Explanation

This problem requires finding the matrix exponential \( e^A \) for a given matrix \( A \). The matrix \( A \) is a 3x3 matrix with the following entries:

\[
A = \begin{bmatrix}
1 & 1 & 2 \\
-1 & 3 & 4 \\
0 & 0 & 2
\end{bmatrix}
\]

### Key Concepts

- **Matrix Exponential:** The matrix exponential \( e^A \) for any square matrix \( A \) is defined as: 
\[
e^A = \sum_{k=0}^{\infty} \frac{A^k}{k!}
\]
This expression involves an infinite series, where \( A^k \) indicates \( A \) raised to the power \( k \) and \( k! \) denotes the factorial of \( k \).

- **Diagonalization (if possible):** If \( A \) is diagonalizable, it can be expressed as \( A = PDP^{-1} \), where \( D \) is a diagonal matrix. Then, \( e^A \) can be computed as \( e^A = Pe^DP^{-1} \), with \( e^D \) being a diagonal matrix where each diagonal element is the exponential of the corresponding diagonal element of \( D \).

- **Jordan Form (if applicable):** For matrices that are not diagonalizable, the Jordan canonical form may be used. \( e^A \) can then be found through a similar process involving the Jordan form.

This concept is widely used in solving systems of differential equations, among other applications in linear algebra and applied mathematics.
Transcribed Image Text:### Problem Statement **2. Find \( e^A \) for** \[ A = \begin{bmatrix} 1 & 1 & 2 \\ -1 & 3 & 4 \\ 0 & 0 & 2 \end{bmatrix} \] ### Explanation This problem requires finding the matrix exponential \( e^A \) for a given matrix \( A \). The matrix \( A \) is a 3x3 matrix with the following entries: \[ A = \begin{bmatrix} 1 & 1 & 2 \\ -1 & 3 & 4 \\ 0 & 0 & 2 \end{bmatrix} \] ### Key Concepts - **Matrix Exponential:** The matrix exponential \( e^A \) for any square matrix \( A \) is defined as: \[ e^A = \sum_{k=0}^{\infty} \frac{A^k}{k!} \] This expression involves an infinite series, where \( A^k \) indicates \( A \) raised to the power \( k \) and \( k! \) denotes the factorial of \( k \). - **Diagonalization (if possible):** If \( A \) is diagonalizable, it can be expressed as \( A = PDP^{-1} \), where \( D \) is a diagonal matrix. Then, \( e^A \) can be computed as \( e^A = Pe^DP^{-1} \), with \( e^D \) being a diagonal matrix where each diagonal element is the exponential of the corresponding diagonal element of \( D \). - **Jordan Form (if applicable):** For matrices that are not diagonalizable, the Jordan canonical form may be used. \( e^A \) can then be found through a similar process involving the Jordan form. This concept is widely used in solving systems of differential equations, among other applications in linear algebra and applied mathematics.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,