Find dy/dx. x = Vt y = 7 - t dy dx

Q: Calculate dy/dx. No need to expand answer. y=7x^2-9x+17/2x+4 dy/dx=

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Q: dy/sec2y=dx/secx

A: Explanation of the answer is as follows

Q: find dy/dxy=3x+xtanx

A: Given:The function y =3x+x(tanx)

Q: y = () Зx2-2 х+3

A: I am using the chain rule to find the first order derivative of the given equation

Q: 1. y = 5u°; u=7x – 4x' + 2x –9 2х-9 u +1. u=Vx? +1 y = u? -1' 3. x=7y -3y +y +8 2.

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Q: Find dy dx Y = x - 7 X

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Q: solve for dy/dx

A: Given that: d. y=coth2x-13e. arctan(y-2x)=x-2y

Q: y = 2cotxArcsec(nx) + cos² ||

A: To find dydx the following rules have to be used: a) Chain rule which states…

Q: 3x2 — 9х + 11 2х + 4

A: Given query is to find the derivative.

Q: find dy/dx for y = -(3x^2 + 5x)^5.

A: solution is given below.