Find d²y dx y = 4x+9

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the second derivative of the function \(y = 4x + 9\) with respect to \(x\).

**Solution:**

1. **First Derivative:**
   - Given \(y = 4x + 9\)
   - Derivative of \(y\) with respect to \(x\), denoted as \(\frac{dy}{dx}\), is:
     \[
     \frac{dy}{dx} = 4
     \]

2. **Second Derivative:**
   - Derivative of \(\frac{dy}{dx} = 4\) with respect to \(x\):
     \[
     \frac{d^2y}{dx^2} = 0
     \]

Since \(4\) is a constant, its derivative with respect to \(x\) is \(0\).

**Conclusion:**
The second derivative \(\frac{d^2y}{dx^2}\) is \(0\), indicating that the original function is linear and has no curvature.
Transcribed Image Text:**Problem Statement:** Find the second derivative of the function \(y = 4x + 9\) with respect to \(x\). **Solution:** 1. **First Derivative:** - Given \(y = 4x + 9\) - Derivative of \(y\) with respect to \(x\), denoted as \(\frac{dy}{dx}\), is: \[ \frac{dy}{dx} = 4 \] 2. **Second Derivative:** - Derivative of \(\frac{dy}{dx} = 4\) with respect to \(x\): \[ \frac{d^2y}{dx^2} = 0 \] Since \(4\) is a constant, its derivative with respect to \(x\) is \(0\). **Conclusion:** The second derivative \(\frac{d^2y}{dx^2}\) is \(0\), indicating that the original function is linear and has no curvature.
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