Find dy dx In (y²) = 4x + 5 - dy dx dy dx dy dx dy dx = = - = 2y -2y 2 K|N Y 2 У

If ` \sqrt(x) + \sqrt (y) = 7`and the point (9, 16) is on the curve, find 'dy/dx|_(x=9)` by implicit differentiation. dy/dx|_(x=9)' : Preview Submit Question

tried to find y" but it says the answer is not -3x^2/5y^2.

Find the derivative dy/dx. Can you please show steps. Thank you.

Considering the equation xy^3+2×^3-×=16 Use implicit differentiation to find dy/dx Then find x when y=1

g(h)=(h+4)^5/h^4 calculate the derivatives

y' of y=(x^4-3x^2+5)^3 and simplified

Find the derivative  a. y= ln(cos^2x) b. y= e^cosx+e^-x

The expression dy/dx = x(cube root^3 y) gives the slope at any point on the graph of the function f(x) where f(2) = 8. - equation of the tangent line f(x) at point (2,8) = (y-8)=4(x-2)- expression for f(x) in terms of x = f(x)=[x^2/3+8/3]^3/2-domain all real numbers.-minimum [8/3]^3/2Using the axes provided, sketch a slope field for the given differential equation at the nine points indicated.

g=X^4+2X^3/X^2,calculate the derivatives