Find C1 and C₂ for the inner product of R2 given by (u, v) = C₁U₁V₁ + C₂U₂V₂ such that the graph represents a unit circle as shown. (C₁, C₂) = (₂) = ( [

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Finding \( c_1 \) and \( c_2 \) for the Inner Product in \( \mathbb{R}^2 \)**

In this exercise, we aim to find the constants \( c_1 \) and \( c_2 \) for the inner product in \( \mathbb{R}^2 \) defined by:

\[ \langle \mathbf{u}, \mathbf{v} \rangle = c_1 u_1 v_1 + c_2 u_2 v_2 \]

such that the graph represents a unit circle as shown in the diagram.

**Equation for Inner Product:**

\[ \langle \mathbf{u}, \mathbf{v} \rangle = c_1 u_1 v_1 + c_2 u_2 v_2 \]

**Condition:**

The graph should represent a unit circle. 

**Solution:**
\[
(c_1, c_2) = \left( \boxed{1, 16} \right)
\]

**Graph Description:**

The graph shown is an ellipse centered at the origin with the equation \( ||\mathbf{u}|| = 1 \). The ellipse intersects the x-axis at points \( x = 4 \) and \( x = -4 \), and the y-axis at points \( y = 1 \) and \( y = -1 \).

**Axes Features:**
- The x-axis ranges from \( -4 \) to \( 4 \).
- The y-axis ranges from \( -4 \) to \( 4 \).

The ellipse represents a transformation of the unit circle under a different inner product defined by \( c_1 \) and \( c_2 \).

**Purpose:**

This configuration will help understand how changing the constants \( c_1 \) and \( c_2 \) in the inner product affects the shape of the unit circle in \( \mathbb{R}^2 \). 

**Graph Representation:**

```plaintext
y
|
4 |                       *                       
3 |                   
2 |               
1 |   *  -------- \||/  -------- *
0 |------------------------------------->  x
-1 |                       *
-2 |   
-3 |
-4 | 
```

The "*" points indicate the intersection points of the ellipse with the axes.

By adjusting \( c_1 \) and \( c_2 \) as
Transcribed Image Text:**Finding \( c_1 \) and \( c_2 \) for the Inner Product in \( \mathbb{R}^2 \)** In this exercise, we aim to find the constants \( c_1 \) and \( c_2 \) for the inner product in \( \mathbb{R}^2 \) defined by: \[ \langle \mathbf{u}, \mathbf{v} \rangle = c_1 u_1 v_1 + c_2 u_2 v_2 \] such that the graph represents a unit circle as shown in the diagram. **Equation for Inner Product:** \[ \langle \mathbf{u}, \mathbf{v} \rangle = c_1 u_1 v_1 + c_2 u_2 v_2 \] **Condition:** The graph should represent a unit circle. **Solution:** \[ (c_1, c_2) = \left( \boxed{1, 16} \right) \] **Graph Description:** The graph shown is an ellipse centered at the origin with the equation \( ||\mathbf{u}|| = 1 \). The ellipse intersects the x-axis at points \( x = 4 \) and \( x = -4 \), and the y-axis at points \( y = 1 \) and \( y = -1 \). **Axes Features:** - The x-axis ranges from \( -4 \) to \( 4 \). - The y-axis ranges from \( -4 \) to \( 4 \). The ellipse represents a transformation of the unit circle under a different inner product defined by \( c_1 \) and \( c_2 \). **Purpose:** This configuration will help understand how changing the constants \( c_1 \) and \( c_2 \) in the inner product affects the shape of the unit circle in \( \mathbb{R}^2 \). **Graph Representation:** ```plaintext y | 4 | * 3 | 2 | 1 | * -------- \||/ -------- * 0 |-------------------------------------> x -1 | * -2 | -3 | -4 | ``` The "*" points indicate the intersection points of the ellipse with the axes. By adjusting \( c_1 \) and \( c_2 \) as
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