Find aw/as and aw/at using the appropriate Chain Rule. Values Function w = y³ - 2x²y s=-3, t = 6 x = es, y = et -4 aw მა Əw at 3e18 aw at 2 X X Evaluate each partial derivative at the given values of s and t. aw 3e18 2 əs -3 X x
Find aw/as and aw/at using the appropriate Chain Rule. Values Function w = y³ - 2x²y s=-3, t = 6 x = es, y = et -4 aw მა Əw at 3e18 aw at 2 X X Evaluate each partial derivative at the given values of s and t. aw 3e18 2 əs -3 X x
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![The task is to find the partial derivatives \(\partial w/\partial s\) and \(\partial w/\partial t\) using the Chain Rule.
**Function:**
\[ w = y^3 - 2x^2y^5 \]
**Values:**
\[ s = -3, \quad t = 6 \]
\[ x = e^s, \quad y = e^t \]
**Partial Derivatives to Find:**
1. \(\partial w/\partial s\)
- Calculation:
\[
\partial w/\partial s = -4
\]
- The given answer (-4) is marked incorrect (indicated by a red "X").
2. \(\partial w/\partial t\)
- Calculation:
\[
\partial w/\partial t = 3e^{18} - 2
\]
- This result is also marked incorrect (indicated by a red "X").
**Evaluation at Given Values:**
- Evaluate each partial derivative at \(s = -3\) and \(t = 6\).
1. \(\partial w/\partial s\)
- Calculation:
\[
\partial w/\partial s = 3e^{18} - 2
\]
- This result is marked incorrect (indicated by a red "X").
2. \(\partial w/\partial t\)
- Calculation:
\[
\partial w/\partial t = -3
\]
- This result is marked incorrect (indicated by a red "X").](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2d6b1a15-ad76-404f-a5e3-cd06c5eb3939%2Fa9afcd3f-67bf-43e4-950f-7d84a8294be5%2F7aeo4mg_processed.png&w=3840&q=75)
Transcribed Image Text:The task is to find the partial derivatives \(\partial w/\partial s\) and \(\partial w/\partial t\) using the Chain Rule.
**Function:**
\[ w = y^3 - 2x^2y^5 \]
**Values:**
\[ s = -3, \quad t = 6 \]
\[ x = e^s, \quad y = e^t \]
**Partial Derivatives to Find:**
1. \(\partial w/\partial s\)
- Calculation:
\[
\partial w/\partial s = -4
\]
- The given answer (-4) is marked incorrect (indicated by a red "X").
2. \(\partial w/\partial t\)
- Calculation:
\[
\partial w/\partial t = 3e^{18} - 2
\]
- This result is also marked incorrect (indicated by a red "X").
**Evaluation at Given Values:**
- Evaluate each partial derivative at \(s = -3\) and \(t = 6\).
1. \(\partial w/\partial s\)
- Calculation:
\[
\partial w/\partial s = 3e^{18} - 2
\]
- This result is marked incorrect (indicated by a red "X").
2. \(\partial w/\partial t\)
- Calculation:
\[
\partial w/\partial t = -3
\]
- This result is marked incorrect (indicated by a red "X").
Expert Solution

Step 1: Define the problem.
To find by using the appropriate Chain Rule.
Function:
Values:
To evaluate each partial derivate at the given values.
Step by step
Solved in 5 steps with 20 images

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