Find and explain the error in the following Z 6 0 1 x − 3 dx = (ln |x − 3|) 6 0 = ln |6 − 3| − ln |0 − 3| = ln(3) − ln(3) = 0.
Find and explain the error in the following Z 6 0 1 x − 3 dx = (ln |x − 3|) 6 0 = ln |6 − 3| − ln |0 − 3| = ln(3) − ln(3) = 0.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
- Find and explain the error in the following
Z 6
0
1
x − 3
dx = (ln |x − 3|)
6
0
= ln |6 − 3| − ln |0 − 3|
= ln(3) − ln(3)
= 0.
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