Find an expression for the inverse of f(x) = e³x+1. f-¹(x) = 4

Q: Are f(x)=3x+5 and g(x)=(x/3)-5 inverse functions? Use function composition.

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Q: Show that the function y = f (x) =-2x +4 is one-to-one and find its inverse function.

A: Here function  fx=-2x+4

Q: F(x)= 7/(x+9) find the inverse

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Q: Verify using Composition of functions that f(x)= 2x+5 and g(x)= (1/2)x - (5/2) are inverse functions…

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Q: x+7 22. (x)= 2x-7, gx) =; 2.

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Q: x + 1 Find the inverse function of f(x) : 2x + 1'

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Q: Sketch the graph of the inverse of l(x) = 4- X.

A: To find the inverse, we plug l(x)=y, then switch x and y and then solve for y So inverse function…

Q: g(x)=-4/x+1 inverse

A: The objective of this question is to find the inverse of the function g(x) = -4/(x+1).

Q: f(x)= 3x-2/ x+1 find the inverse

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Q: 5/3 Find the inverse of f(x)= X

A: See attached file for a step by step explanation.

Q: Find the inverse function  y=g(x)=√t-3 g-1(y)=

A: The given function should be

Q: Find the inverse function of  f(x) =  x − 2 3x + 3

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Q: The graph of the function r(x) = (−x)^3 / 20 is shown here. Draw a graph of the inverse function,…

A: Inverse function is nothing but the reflection of the main graph about the line y=x

Q: Find the inverse function f-1(x) if f(x) =x +5.

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Q: f(x)=x^3+8 Compute the inverse of ?(?)f(x), and name the inverse ?(?)g(x). Show your work

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Q: The function f(x) = x - 3 / x - 4 , x ≠ 4, is one-to-one. Find its inverse function.

A: Given: fx=x-3x-4 , x≠4 is one to one function.

Q: Which equation is the inverse of f (x) = 3x + 4? Af(x) = 4x – 3 1 4 f (x) = 3 B 3 Of (x) = 3x – 4 1…

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Q: Find the inverse of g (x) = ÷x +. g1 (x) = *x -

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Q: The function f is defined by f (x) = -x³ + 3x² – 3x and f(2) =-2. If g is the inverse function of f,…

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Q: erse of f (x) = }x +1. w

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Q: Find the inverse function of f(x) = 19 + x. f-(x) =

A: We have to find the inverse function from the given function

Q: Find the inverse of f(x) = (x + 1) / (x - 5), x ≠ 5.

A: Given:            f(x) = x+1x-5, x≠ 5

Q: Find the inverse of g (x) = } x + }

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