Find an equation of the tangent line to the graph of the function at the given point. y =V2x + 8x, (2, 2) y = Use a graphing utility to graph the function and the tangent line in the same viewing window. y 7 6 4 3 2 2 The xyteodrdirtete'nighe-gnten.There durrt ertdine o the Zrefi 5-4 -3-21 1 2 3 4 5 6 7 • The curve enters the windtow.in the second quadrant, goes down and right becomit more steep, passes through the origin nearly vertical, ggs down and rightbecoming less steep, passes through the point (2, -2) touching he line, and exits the window The fourth quadrant. • The line enters the winsw in the second quadrant, goes down and right, crosseg the x-axis at x -3, crosses the y-axis at y-1.2, pass through the point (2, -2) touching the curve, andexits the window in the fourth quadrant. -7-6-8-4-3-2-1, 1 2 3 4 5 6 7 -7-6-5-43-2-1, 1 2 3 4 5 6 7 -2 -3 -3 -4 -4 -5 -5 -6 -6 2 -7-6-5-4-3-2- 1 2 3 45 6 7

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find an equation of the tangent line to the graph of the function at the given point.
y = V2x3 + 8x, (2, 2)
y =
Use a graphing utility to graph the function and the tangent linei
the same viewing window.
y
y
y
7
5
4
2
The xycodrdirtate plahe is giten. There i i durve artd Hine ox
the Zrafh- 5-4-3-2-1,
• The curve enters the window in the second quadrant, goes
down and right becoming more steep, passes through the
origin nearly vertical, goes down and right becoming less
steep, passes through the point (2, -2) touching the line,
and exits the window inthe fourth quadrant.
• The line enters the wingcw in the second quadrant, goes
down and right, crosseş.the x-axis at x = -3, crosses the
y-axis at y = -1.2, pases through the point (2, -2)
touching the curve, andexits the window in the fourth
quadrant.
-7-6-5-4-3-2-1
1
2 3
5 6 7
1 2 3 4 5 6 7
-7-6-5-443-2-1.
1 2 3 4 5
6 7
y
7
6
3
2
-7-6-5-4-3-2- 1 2 3 4 5 6 7
Transcribed Image Text:Find an equation of the tangent line to the graph of the function at the given point. y = V2x3 + 8x, (2, 2) y = Use a graphing utility to graph the function and the tangent linei the same viewing window. y y y 7 5 4 2 The xycodrdirtate plahe is giten. There i i durve artd Hine ox the Zrafh- 5-4-3-2-1, • The curve enters the window in the second quadrant, goes down and right becoming more steep, passes through the origin nearly vertical, goes down and right becoming less steep, passes through the point (2, -2) touching the line, and exits the window inthe fourth quadrant. • The line enters the wingcw in the second quadrant, goes down and right, crosseş.the x-axis at x = -3, crosses the y-axis at y = -1.2, pases through the point (2, -2) touching the curve, andexits the window in the fourth quadrant. -7-6-5-4-3-2-1 1 2 3 5 6 7 1 2 3 4 5 6 7 -7-6-5-443-2-1. 1 2 3 4 5 6 7 y 7 6 3 2 -7-6-5-4-3-2- 1 2 3 4 5 6 7
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