Find an equation of the plane passing through the given points (2, 9, –9), (2, –9, 9), (-2, –9, –9)
Find an equation of the plane passing through the given points (2, 9, –9), (2, –9, 9), (-2, –9, –9)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![**Problem Statement**:
Find an equation of the plane passing through the given points.
**Given Points**:
\((2, 9, -9)\), \((2, -9, 9)\), \((-2, -9, -9)\)
**Diagram Description**:
There is a blank rectangular box, presumably for the answer or calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8268c271-8991-49a2-aed9-a02bde5bd8ab%2F7ec3c2fe-6807-4b99-a11c-290301963ca2%2Fo1uh9k_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement**:
Find an equation of the plane passing through the given points.
**Given Points**:
\((2, 9, -9)\), \((2, -9, 9)\), \((-2, -9, -9)\)
**Diagram Description**:
There is a blank rectangular box, presumably for the answer or calculations.
![**Determine whether Cramer's Rule is used correctly to solve for the variable. If not, identify the mistake.**
\[
\begin{aligned}
x + 3y + z &= 3 \\
-x + 4y - 3z &= 2 \\
2x + y - z &= 6 \\
\end{aligned}
\]
\[
y = \frac{\begin{vmatrix} 1 & \textcolor{red}{3} & 1 \\ -1 & 4 & -3 \\ 2 & 1 & -1 \end{vmatrix}}{\begin{vmatrix} 1 & \textcolor{red}{3} & 1 \\ -1 & \textcolor{red}{2} & -3 \\ 2 & \textcolor{red}{6} & -1 \end{vmatrix}}
\]
- **Option A**: The numerator and denominator have been reversed. The determinant of the coefficient matrix should be in the denominator.
- **Option B**: The row of constants should be in the second row.
- **Option C**: There is no mistake.
- **Option D**: The column of constants should be in the first column.
- **Option E**: The numerator and denominator have been reversed. The determinant of the coefficient matrix should be in the numerator.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8268c271-8991-49a2-aed9-a02bde5bd8ab%2F7ec3c2fe-6807-4b99-a11c-290301963ca2%2Fx2lhljk_processed.png&w=3840&q=75)
Transcribed Image Text:**Determine whether Cramer's Rule is used correctly to solve for the variable. If not, identify the mistake.**
\[
\begin{aligned}
x + 3y + z &= 3 \\
-x + 4y - 3z &= 2 \\
2x + y - z &= 6 \\
\end{aligned}
\]
\[
y = \frac{\begin{vmatrix} 1 & \textcolor{red}{3} & 1 \\ -1 & 4 & -3 \\ 2 & 1 & -1 \end{vmatrix}}{\begin{vmatrix} 1 & \textcolor{red}{3} & 1 \\ -1 & \textcolor{red}{2} & -3 \\ 2 & \textcolor{red}{6} & -1 \end{vmatrix}}
\]
- **Option A**: The numerator and denominator have been reversed. The determinant of the coefficient matrix should be in the denominator.
- **Option B**: The row of constants should be in the second row.
- **Option C**: There is no mistake.
- **Option D**: The column of constants should be in the first column.
- **Option E**: The numerator and denominator have been reversed. The determinant of the coefficient matrix should be in the numerator.
Expert Solution
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Step 1
(A) To find the equation of plane passing through below points.
(B) To determine the correct statement.
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