Find an equation of the normal line to the surface given implicitly by z = sin(xy) at the point (5,-1, -1³). Lütfen birini seçin: T √√3 -ty=-1+t, z = -- - t.teR 2 2 bz = -¹/t₁y = −1+ t.2 = √3 t. - t.teR 2 x = -1/2+²t₁y = -t, z = -1 t.teR √3 dz=-t₁y=+=--t.teR 3 √3 ²z=-1-t₁y = -1 +2=-1-tte R 2 >2 √3

Q: Find the tangent line to the curve y = x + 2x3-2x2 -3x + 3 which is perpendicular to the line x- 3y…

A: Given :y=x4+2x3-2x2-3x+3Line : x-3y=2

Q: Find the tangent plane to the equation z = 2x² 2= 56x-430y + 1554 X 2x²2y² + 4y at the point (3, 4,…

A:

Q: 3. Find the equation of the tangent line to the parabola 4x² +9y² = 18z, x = 3 at the point (3, 2,…

A:

Q: II. Find the equations of the tangent and normal lines at the point indicated. a. 7x - 6V3ry + 13y -…

A: Solution is given below: