Find an equation of the normal line to the surface given implicitly by z = sin(xy) at the point (5,-1, -1³). Lütfen birini seçin: T √√3 -ty=-1+t, z = -- - t.teR 2 2 bz = -¹/t₁y = −1+ t.2 = √3 t. - t.teR 2 x = -1/2+²t₁y = -t, z = -1 t.teR √3 dz=-t₁y=+=--t.teR 3 √3 ²z=-1-t₁y = -1 +2=-1-tte R 2 >2 √3

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