Find an equation of the line parallel to 7x-y=5 and passing through (4,3). Express the equation in standard form. Which of the following is the equation of a line parallel to 7x - y = 5 and passing through (4,3)? 4 OA. 7x-y=25 OB. 7x-y-31 OC. x+7y=25 O D. x + 7y=31

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Question 4 of 20

**Problem Statement:**

Find an equation of the line parallel to \(7x - y = 5\) and passing through \((4, 3)\). Express the equation in standard form.

**Question:**

Which of the following is the equation of a line parallel to \(7x - y = 5\) and passing through \((4, 3)\)?

**Options:**
- A. \(7x - y = 25\)
- B. \(7x - y = 31\)
- C. \(x + 7y = 25\)
- D. \(x + 7y = 31\)

**Explanation:**

Parallel lines have the same slope. The given line’s equation is \(7x - y = 5\).

Rewrite the given line’s equation in slope-intercept form (y = mx + b):
\[ y = 7x - 5 \]
The slope \( m \) is 7. 

For the line to be parallel, it must have the same slope \( m = 7 \).

Use the point \((4, 3)\) to find the new line’s equation:

Substitute \( (x, y) = (4, 3) \) and \( m = 7 \) into the point-slope form:
\[ y - 3 = 7(x - 4) \]
\[ y - 3 = 7x - 28 \]
\[ y = 7x - 25 \]

Rewrite in standard form by rearranging:
\[ 7x - y = 25 \]

So, the answer is option A: \(7x - y = 25\).
Transcribed Image Text:### Question 4 of 20 **Problem Statement:** Find an equation of the line parallel to \(7x - y = 5\) and passing through \((4, 3)\). Express the equation in standard form. **Question:** Which of the following is the equation of a line parallel to \(7x - y = 5\) and passing through \((4, 3)\)? **Options:** - A. \(7x - y = 25\) - B. \(7x - y = 31\) - C. \(x + 7y = 25\) - D. \(x + 7y = 31\) **Explanation:** Parallel lines have the same slope. The given line’s equation is \(7x - y = 5\). Rewrite the given line’s equation in slope-intercept form (y = mx + b): \[ y = 7x - 5 \] The slope \( m \) is 7. For the line to be parallel, it must have the same slope \( m = 7 \). Use the point \((4, 3)\) to find the new line’s equation: Substitute \( (x, y) = (4, 3) \) and \( m = 7 \) into the point-slope form: \[ y - 3 = 7(x - 4) \] \[ y - 3 = 7x - 28 \] \[ y = 7x - 25 \] Rewrite in standard form by rearranging: \[ 7x - y = 25 \] So, the answer is option A: \(7x - y = 25\).
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