Find an equation for the tangent to the curve at P. y = 1+ sec x 4 y = V2x - + 1 + 2 y = - - y = - 2x - 1 - 2 O y= V2x+ 1+ 2 de 5.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Find an equation for the tangent to the curve at P.**

**Equation of the Curve:**  
\[ y = 1 + \sec x \]

**Point P on the Curve:**  
\[ P \left( \frac{\pi}{4}, 1 + \sqrt{2} \right) \]

**Graph Explanation:**
- The graph shows the curve of \( y = 1 + \sec x \).
- The x-axis ranges from \( -\frac{\pi}{2} \) to \( \frac{\pi}{2} \).
- The y-axis is labeled with integers from -2 to 6.
- The curve appears to have a vertical asymptote at \( x = -\frac{\pi}{2} \) and \( x = \frac{\pi}{2} \).
- The point \( P \left( \frac{\pi}{4}, 1 + \sqrt{2} \right) \) is marked on the curve.

**Possible Tangent Equations:**

1. \[ y = \sqrt{2}x - \frac{\pi \sqrt{2}}{4} + 1 + \sqrt{2} \]

2. \[ y = -\sqrt{2}x + \frac{\pi \sqrt{2}}{4} - 1 - \sqrt{2} \]

3. \[ y = -\sqrt{2}x - 1 - \sqrt{2} \]

4. \[ y = \sqrt{2}x + 1 + \sqrt{2} \]

**Task:** Determine which equation is the correct one for the tangent to the curve at the given point \( P \).
Transcribed Image Text:**Find an equation for the tangent to the curve at P.** **Equation of the Curve:** \[ y = 1 + \sec x \] **Point P on the Curve:** \[ P \left( \frac{\pi}{4}, 1 + \sqrt{2} \right) \] **Graph Explanation:** - The graph shows the curve of \( y = 1 + \sec x \). - The x-axis ranges from \( -\frac{\pi}{2} \) to \( \frac{\pi}{2} \). - The y-axis is labeled with integers from -2 to 6. - The curve appears to have a vertical asymptote at \( x = -\frac{\pi}{2} \) and \( x = \frac{\pi}{2} \). - The point \( P \left( \frac{\pi}{4}, 1 + \sqrt{2} \right) \) is marked on the curve. **Possible Tangent Equations:** 1. \[ y = \sqrt{2}x - \frac{\pi \sqrt{2}}{4} + 1 + \sqrt{2} \] 2. \[ y = -\sqrt{2}x + \frac{\pi \sqrt{2}}{4} - 1 - \sqrt{2} \] 3. \[ y = -\sqrt{2}x - 1 - \sqrt{2} \] 4. \[ y = \sqrt{2}x + 1 + \sqrt{2} \] **Task:** Determine which equation is the correct one for the tangent to the curve at the given point \( P \).
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