Find an equation for the plane tangent to the surface e z = x cos(xz) – y at the point (2, 1,0).

Trigonometry (MindTap Course List)
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Chapter6: Topics In Analytic Geometry
Section6.6: Parametric Equations
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**Finding the Tangent Plane Equation to the Given Surface**

To find an equation for the plane tangent to the surface \(e^{yz} = x \cos(xz) - y\) at the point (2, 1, 0), we need to follow these steps:

1. **Write the surface equation:**
   \[
   F(x, y, z) = e^{yz} - x \cos(xz) + y
   \]

2. **Compute the partial derivatives of \(F(x, y, z)\):**
   \[
   F_x = \frac{\partial}{\partial x} \left(e^{yz} - x \cos(xz) + y\right)
   \]
   \[
   F_y = \frac{\partial}{\partial y} \left(e^{yz} - x \cos(xz) + y\right)
   \]
   \[
   F_z = \frac{\partial}{\partial z} \left(e^{yz} - x \cos(xz) + y\right)
   \]

3. **Evaluate the partial derivatives at the given point (2, 1, 0):**
   - Calculate \(F_x(2, 1, 0)\)
   - Calculate \(F_y(2, 1, 0)\)
   - Calculate \(F_z(2, 1, 0)\)

4. **Use the formula for the tangent plane:**
   \[
   F_x(x_0, y_0, z_0) (x - x_0) + F_y(x_0, y_0, z_0) (y - y_0) + F_z(x_0, y_0, z_0) (z - z_0) = 0
   \]

By performing these calculations, we can derive the specific equation for the tangent plane at the point (2, 1, 0).

\[
\text{Detailed solution steps including the computation of partial derivatives and evaluations are provided below:}
\]

**Step-by-Step Solution:**

1. Calculate \(F_x\):
   \[
   F_x = -\cos(xz) + xz \sin(xz)
   \]
   Evaluate \(F_x\) at (2, 1, 0):
   \[
   F_x(2, 1,
Transcribed Image Text:**Finding the Tangent Plane Equation to the Given Surface** To find an equation for the plane tangent to the surface \(e^{yz} = x \cos(xz) - y\) at the point (2, 1, 0), we need to follow these steps: 1. **Write the surface equation:** \[ F(x, y, z) = e^{yz} - x \cos(xz) + y \] 2. **Compute the partial derivatives of \(F(x, y, z)\):** \[ F_x = \frac{\partial}{\partial x} \left(e^{yz} - x \cos(xz) + y\right) \] \[ F_y = \frac{\partial}{\partial y} \left(e^{yz} - x \cos(xz) + y\right) \] \[ F_z = \frac{\partial}{\partial z} \left(e^{yz} - x \cos(xz) + y\right) \] 3. **Evaluate the partial derivatives at the given point (2, 1, 0):** - Calculate \(F_x(2, 1, 0)\) - Calculate \(F_y(2, 1, 0)\) - Calculate \(F_z(2, 1, 0)\) 4. **Use the formula for the tangent plane:** \[ F_x(x_0, y_0, z_0) (x - x_0) + F_y(x_0, y_0, z_0) (y - y_0) + F_z(x_0, y_0, z_0) (z - z_0) = 0 \] By performing these calculations, we can derive the specific equation for the tangent plane at the point (2, 1, 0). \[ \text{Detailed solution steps including the computation of partial derivatives and evaluations are provided below:} \] **Step-by-Step Solution:** 1. Calculate \(F_x\): \[ F_x = -\cos(xz) + xz \sin(xz) \] Evaluate \(F_x\) at (2, 1, 0): \[ F_x(2, 1,
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