Find an equation for each line that passes through the point (4, 3) and is tangent to the parametric curve = 3t² + 1, y = 2t³ + 1. If there is more than one answer then order your answers consecutively so lines with smaller slopes appear before lines with larger slopes. If some answer fields are not used enter None in the unused answer blanks and list them last. Tangent line 1: y = Tangent line 2: y = x = Tangent line 3: y =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find an equation for each line that passes through the point (4, 3) and is tangent to the parametric curve
3t²+1, y =
= 2t³
+1.
If there is more than one answer then order your answers consecutively so lines with smaller slopes appear before lines
with larger slopes. If some answer fields are not used enter None in the unused answer blanks and list them last.
Tangent line 1: y =
Tangent line 2: y =
X =
Tangent line 3: y =
Transcribed Image Text:Find an equation for each line that passes through the point (4, 3) and is tangent to the parametric curve 3t²+1, y = = 2t³ +1. If there is more than one answer then order your answers consecutively so lines with smaller slopes appear before lines with larger slopes. If some answer fields are not used enter None in the unused answer blanks and list them last. Tangent line 1: y = Tangent line 2: y = X = Tangent line 3: y =
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