Find an arc length parametrization r₁ (s) of the curve r(t) = (71,3/2, 103/2), with the parameter s measuring from (0, 0, 0). (Use symbolic notation and fractions where needed.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Title: Arc Length Parametrization of a Curve**

**Concept**: To find an arc length parametrization \( \mathbf{r}_1(s) \) of the given curve \( \mathbf{r}(t) \), where the parameter \( s \) measures the arc length from the point \( (0, 0, 0) \).

**Given Curve**: 
\[ 
\mathbf{r}(t) = \left\langle 7t, \frac{10}{3}t^{3/2}, \frac{10}{\sqrt{3}}t^{3/2} \right\rangle 
\]

**Instruction**: Use symbolic notation and fractions where needed.

**Solution**:

The solution presented in the image was:
\[ 
\mathbf{r}_1(s) = \left\langle \frac{550}{\sqrt{901}}, \frac{16500}{\sqrt{901}}  \right\rangle 
\]
This solution has been marked as "Incorrect".

**Approach**:
To find the correct arc length parametrization, we typically follow these steps:

1. **Compute \(\mathbf{r}'(t)\)**:
   The derivative of \( \mathbf{r}(t) \) with respect to \( t \).

2. **Compute the magnitude of \( \mathbf{r}'(t) \)**:
   \[ \left| \mathbf{r}'(t) \right| \]

3. **Express \( s \) as a function of \( t \)**:
   Integrate the magnitude of \( \mathbf{r}'(t) \) to find \( s \).

4. **Solve for \( t \) in terms of \( s \) and substitute back to get \( \mathbf{r}_1(s) \)**.

Since the solution provided in the image was incorrect, revisiting these steps will be necessary to find the accurate parameterization.

---

**Note for educators**: This process helps students understand the conversion between parametric curves and their arc-length parametrizations, reinforcing concepts in differential calculus, vector calculus, and integral calculus.
Transcribed Image Text:**Title: Arc Length Parametrization of a Curve** **Concept**: To find an arc length parametrization \( \mathbf{r}_1(s) \) of the given curve \( \mathbf{r}(t) \), where the parameter \( s \) measures the arc length from the point \( (0, 0, 0) \). **Given Curve**: \[ \mathbf{r}(t) = \left\langle 7t, \frac{10}{3}t^{3/2}, \frac{10}{\sqrt{3}}t^{3/2} \right\rangle \] **Instruction**: Use symbolic notation and fractions where needed. **Solution**: The solution presented in the image was: \[ \mathbf{r}_1(s) = \left\langle \frac{550}{\sqrt{901}}, \frac{16500}{\sqrt{901}} \right\rangle \] This solution has been marked as "Incorrect". **Approach**: To find the correct arc length parametrization, we typically follow these steps: 1. **Compute \(\mathbf{r}'(t)\)**: The derivative of \( \mathbf{r}(t) \) with respect to \( t \). 2. **Compute the magnitude of \( \mathbf{r}'(t) \)**: \[ \left| \mathbf{r}'(t) \right| \] 3. **Express \( s \) as a function of \( t \)**: Integrate the magnitude of \( \mathbf{r}'(t) \) to find \( s \). 4. **Solve for \( t \) in terms of \( s \) and substitute back to get \( \mathbf{r}_1(s) \)**. Since the solution provided in the image was incorrect, revisiting these steps will be necessary to find the accurate parameterization. --- **Note for educators**: This process helps students understand the conversion between parametric curves and their arc-length parametrizations, reinforcing concepts in differential calculus, vector calculus, and integral calculus.
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