Find all the roots of z2= -1+ /3j It A z=V2 (cos (-+ kn) +j sin (-+kn)),k=-1,0 3 B z=V2 (cos (-+ kx) +j sin ( -+kx)), k=0, 1 6. z=2 (cos +j sin-) 3 z=V2 (cos ( + kx) +j sin ( 12 +kx)), k 0, I 12 D

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find all the roots of
z²= - 1+ /3j
A
z=V2 (cos (-+ka) +j sin(-+ka)),k=-1,0
3
元
B
=V2 (cos (-+kx) +j sin (- + ka)), k=0, 1
В
C
z=2 (cos -+j sin-)
3
3.
D) z=V2 (cos (-+kx)+/ sin (+kr)), k=0, 1
12
+ ka)), k=0, I
12
Transcribed Image Text:Find all the roots of z²= - 1+ /3j A z=V2 (cos (-+ka) +j sin(-+ka)),k=-1,0 3 元 B =V2 (cos (-+kx) +j sin (- + ka)), k=0, 1 В C z=2 (cos -+j sin-) 3 3. D) z=V2 (cos (-+kx)+/ sin (+kr)), k=0, 1 12 + ka)), k=0, I 12
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