Find all the local maxima, local minima, and saddle points of the function. f(x,y)=2xy-x²-6y² + 2x+4 Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. A. 61 5'5 (Type an ordered pair. Use a comma to separate answers as needed.) 26 A local maximum occurs at The local maximum value(s) is/are (Type an exact answer. Use a comma to separate answers as needed.) B. There are no local maxima. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. OA. A local minimum occurs at (Type an ordered pair. Use a comma to separate answers as needed.) The local minimum value(s) is/are (Type an exact answer. Use a comma to separate answers as needed.) B. There are no local minima.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Pls solve minima & saddle points. Thank you & I will give thumbs up.

**Problem Statement:**

Find all the local maxima, local minima, and saddle points of the function.

\[ f(x, y) = 2xy - x^2 - 6y^2 + 2x + 4 \]

**Solution:**

1. **Local Maxima:**

   - **Option A:**
     - A local maximum occurs at \(\left(\frac{6}{5}, \frac{1}{5}\right)\).
     - The local maximum value is \(\frac{26}{5}\).
   
   - **Option B:**
     - There are no local maxima.

   (The correct option is selected as **A**, indicating there is a local maximum at the specified point.)

2. **Local Minima:**

   - **Option A:**
     - A local minimum occurs at [fill in blank].
     - The local minimum value is [fill in blank].
   
   - **Option B:**
     - There are no local minima.

   (There is no selection made, indicating further work is required to determine local minima.)
Transcribed Image Text:**Problem Statement:** Find all the local maxima, local minima, and saddle points of the function. \[ f(x, y) = 2xy - x^2 - 6y^2 + 2x + 4 \] **Solution:** 1. **Local Maxima:** - **Option A:** - A local maximum occurs at \(\left(\frac{6}{5}, \frac{1}{5}\right)\). - The local maximum value is \(\frac{26}{5}\). - **Option B:** - There are no local maxima. (The correct option is selected as **A**, indicating there is a local maximum at the specified point.) 2. **Local Minima:** - **Option A:** - A local minimum occurs at [fill in blank]. - The local minimum value is [fill in blank]. - **Option B:** - There are no local minima. (There is no selection made, indicating further work is required to determine local minima.)
Expert Solution
Step 1: Given the information

The given function is f open parentheses x comma space y close parentheses equals 2 x y minus x squared minus 6 y squared plus 2 x plus 4.

The aim is to find the local maximum, local minimum, and saddle point of the function.

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