Find all solutions to 2cos(θ)=√2  on the interval 0≤θ<2π0≤θ<2π θ =

Q: One of the values of x from the equation 2 csc(x) = 4 over the interval [0, 2π) is 5.

A:

Q: (c) f(y) = √√2y + (3y + 4y²)³ 1-t (d) g(t) = sin³ (e¹−t + 3 sin(6t))

A:

Q: Find θ with 0≤θ<2π and cscθ=2

A:

Q: Find θ with 0≤θ<2π  and tanθ=1

A: 0≤θ&lt;2π  and tanθ=1

Q: A sketch of y = sin x° for-360 ≤ x ≤ 360 is shown.

A: Step 1: As we know π= 180⁰So 360 can be written as 360⁰=2πAnd -360°= -2π That is X lies between -2π…

Q: Find the range of y =cos4x - 1. 1 sys 2 1 2 -5 sys3 3 3 sys 2 2 1 <ys 1

A: The graph is shown below: