Find all solutions of the equation in the interval [0, 27T). (Enter your answers as a comma-separated lis 37 sin x + 2 cos? x = 0

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Solving Trigonometric Equation

#### Problem Statement:
Find all solutions of the equation in the interval \([0, 2\pi)\). (Enter your answers as a comma-separated list.)

\[ \sin\left(x + \frac{3\pi}{2}\right) - \cos^2 x = 0 \]

\[ x = \_\_\_\_\_ \]

#### Explanation:

To solve this equation, we will use the properties of trigonometric functions and identities.

1. **Rewrite the equation using trigonometric identities**:
   
   The term \(\sin\left(x + \frac{3\pi}{2}\right)\) can be simplified using the sine addition formula:
   
   \[
   \sin\left(x + \frac{3\pi}{2}\right) = \sin x \cos \frac{3\pi}{2} + \cos x \sin \frac{3\pi}{2}
   \]
   
   We know that:
   
   \[
   \cos \frac{3\pi}{2} = 0 \quad \text{and} \quad \sin \frac{3\pi}{2} = -1
   \]
   
   Therefore:
   
   \[
   \sin\left(x + \frac{3\pi}{2}\right) = \sin x \cdot 0 + \cos x \cdot (-1) = -\cos x
   \]
   
   The original equation simplifies to:
   
   \[
   -\cos x - \cos^2 x = 0
   \]

2. **Factor the equation**:

   \[
   -\cos x (1 + \cos x) = 0
   \]

3. **Solve for \(\cos x\)**:

   Setting each factor to zero gives us:
   
   \[
   -\cos x = 0 \quad \text{or} \quad 1 + \cos x = 0
   \]
   
   \[
   \cos x = 0 \quad \text{or} \quad \cos x = -1
   \]

4. **Find the values of \(x\) within the given interval \([0, 2\pi)\)**:

   - For \(\cos x = 0\):
     \[
     x = \frac{\
Transcribed Image Text:### Solving Trigonometric Equation #### Problem Statement: Find all solutions of the equation in the interval \([0, 2\pi)\). (Enter your answers as a comma-separated list.) \[ \sin\left(x + \frac{3\pi}{2}\right) - \cos^2 x = 0 \] \[ x = \_\_\_\_\_ \] #### Explanation: To solve this equation, we will use the properties of trigonometric functions and identities. 1. **Rewrite the equation using trigonometric identities**: The term \(\sin\left(x + \frac{3\pi}{2}\right)\) can be simplified using the sine addition formula: \[ \sin\left(x + \frac{3\pi}{2}\right) = \sin x \cos \frac{3\pi}{2} + \cos x \sin \frac{3\pi}{2} \] We know that: \[ \cos \frac{3\pi}{2} = 0 \quad \text{and} \quad \sin \frac{3\pi}{2} = -1 \] Therefore: \[ \sin\left(x + \frac{3\pi}{2}\right) = \sin x \cdot 0 + \cos x \cdot (-1) = -\cos x \] The original equation simplifies to: \[ -\cos x - \cos^2 x = 0 \] 2. **Factor the equation**: \[ -\cos x (1 + \cos x) = 0 \] 3. **Solve for \(\cos x\)**: Setting each factor to zero gives us: \[ -\cos x = 0 \quad \text{or} \quad 1 + \cos x = 0 \] \[ \cos x = 0 \quad \text{or} \quad \cos x = -1 \] 4. **Find the values of \(x\) within the given interval \([0, 2\pi)\)**: - For \(\cos x = 0\): \[ x = \frac{\
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