Find all prime implicants of the following function and then find all minimum solutions using Petrick's method: F(A, B, C, D) = { m(9, 12, 13, 15) + Σ d(1, 4, 5, 7, 8, 11, 14)
Find all prime implicants of the following function and then find all minimum solutions using Petrick's method: F(A, B, C, D) = { m(9, 12, 13, 15) + Σ d(1, 4, 5, 7, 8, 11, 14)
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![Find all prime implicants of the following function and then find all minimum
solutions using Petrick's method:
F(A, B, C, D) = Σ m(9, 12, 13, 15) + Σ d(1, 4, 5, 7, 8, 11, 14)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1e554a09-0f9c-418e-bf2f-f101c15adca6%2Fbf1331e6-f026-4f02-8654-42dc10ae8a61%2Frsil9iv_processed.png&w=3840&q=75)
Transcribed Image Text:Find all prime implicants of the following function and then find all minimum
solutions using Petrick's method:
F(A, B, C, D) = Σ m(9, 12, 13, 15) + Σ d(1, 4, 5, 7, 8, 11, 14)
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Follow-up Question
how to use pertrick's method?
![To find
Petrick's fable,
From
P₁ (1,5,9,13)
P₂
P3
Pu
Ps
minimum
P
minimum
minimum
(1,5,12,13)
Solution using petrick's method forming
(5,7,13,15)
(8,9,12,13)
(9,11,13,15)
(12, 13, 14, 15)
F5
FG
which
C'D
Bet
BD
Ac X
AD
= P4 +PG
197
X
AB
Yow!
Solutions are,
F₁ = P₁ + P = c'D+AB
F2₂ = ₁₂ + 5 =Bc' + AD
F3 = P3 + P4
f4 =
хх
BD+Ac
P+Ps = Ac+AD
=
ActAB
P5+ = AD+ AB
19 13
X
above table, au posible choices by taking
X
X
XX
Х Х Х Х
15
X
X
Covers at the minterms. Then all
XX
XX](https://content.bartleby.com/qna-images/question/1e554a09-0f9c-418e-bf2f-f101c15adca6/b110193e-11fe-491d-b8b1-b955b5cf213c/tpr7wfd_thumbnail.jpeg)
Transcribed Image Text:To find
Petrick's fable,
From
P₁ (1,5,9,13)
P₂
P3
Pu
Ps
minimum
P
minimum
minimum
(1,5,12,13)
Solution using petrick's method forming
(5,7,13,15)
(8,9,12,13)
(9,11,13,15)
(12, 13, 14, 15)
F5
FG
which
C'D
Bet
BD
Ac X
AD
= P4 +PG
197
X
AB
Yow!
Solutions are,
F₁ = P₁ + P = c'D+AB
F2₂ = ₁₂ + 5 =Bc' + AD
F3 = P3 + P4
f4 =
хх
BD+Ac
P+Ps = Ac+AD
=
ActAB
P5+ = AD+ AB
19 13
X
above table, au posible choices by taking
X
X
XX
Х Х Х Х
15
X
X
Covers at the minterms. Then all
XX
XX
Solution
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