Find all Nash equilibria using the table method. Use / for column dominance and \ for row dominance. Put both / and \ if both apply; i.e. check every cell for both row and column elimination. After using algebra to resolve any surviving cells, plug your strategies back into the game and compute payoffs to verify your solutions. Show all your work. NO CALCULATORS or decimal answers - use fractions!
Find all Nash equilibria using the table method. Use / for column dominance and \ for row dominance. Put both / and \ if both apply; i.e. check every cell for both row and column elimination. After using algebra to resolve any surviving cells, plug your strategies back into the game and compute payoffs to verify your solutions. Show all your work. NO CALCULATORS or decimal answers - use fractions!
Chapter1: Making Economics Decisions
Section: Chapter Questions
Problem 1QTC
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Please refer to the ideas and solutions given in the examples.
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Transcribed Image Text:Find all Nash equilibria using the table method. Use / for column dominance and \
for row dominance. Put both / and \ if both apply; i.e. check every cell for both
row and column elimination. After using algebra to resolve any surviving cells,
plug your strategies back into the game and compute payoffs to verify your
solutions. Show all your work. NO CALCULATORS or decimal answers - use
fractions!
1,2 0,3
-1,-2 2,-2
1,1
1,0
2,1
-3,0
-1,-1
1
2
3
12
13
23
123
1
2
3
12 13 23 123

Transcribed Image Text:Find all Nash equilibria using the table method. Use / for column dominance and \
for row dominance. Put both / and \ if both apply; i.e. check every cell for both
row and column elimination. After using algebra to analyze any surviving cells,
plug your strategies back into the game and compute payoffs to verify your
solutions. Show all your work. NO CALCULATORS or decimal answers - use
fractions! Thank you!
0
1/3
1/2 2/7 1/2 1,2
1/2 3/7 0
0 2/7 1/2
1
1
A
A
A
A
2
3
12
13 1
23 1
123 1
-1,-2
3,1
2
1
1
A
1
1
A
1
3/2
0/2
E: need p2(x,c1)=p2(x,c2)=p2(x,c3) and
p1(r1,y) = p1(r2,y) = p1(r3,y). yB makes all 3
rows pay the same, and it is the unique mixture
that does so, so there are no NE in cell E.
3
7
1
^
1
A
1
1
12
1
1
1
/
B
I
C
5/6
2/3
1,3
2,-2
0,0
3/2
1/2
-x1+0x2+1(1-x1-x2) = 0
-2x1 - x2 + 1 = 0
2x1 + x2 = 1
13
1
A
/
A
1
1
1
1/6
0
2,1 1 7/6
-3,0 1 7/6
-1,-1 1-1/6
0
1/2
23 123
1
1
/
1
A
D
1
A
1
A /
E
1
A: XA=(0,0,1)= r3, yA=(1,0,0)= c1
B: xB=(1/2, 0, 1/2), yB=(1/3, 2/3, 0)
C: yC=yB, xC must satisfy
p2(x,c1)=p2(x,c2)>=p2(x,c3)
2x1-2x2+1(1-x2-x3)
-[3x1-2x2+0(
-[1x1+0x2-1(
D: xD must satisfy
p2(x,c2)=p2(x,c3)>=p2(x,c1)
X~
3x1-2(1-x2)
-[ 1x1+0(1-x1)
2x1-2(1-x1)= 0
x1 = x2 = 1/2
yD must satisfy
p1(r1,y)=p1(r2,y)>=p1(r3,y)
1y2+2(1-y2)
-[2y2-3(1-y2)
-y2+5(1-y2)= 0
5-6y2 = 0
The set of x's that satisfy both the equation
and the inequalities.
NE = {(x,y) | y = (1/3, 2/3, 0),
2x1-2x2+1(1-x2-x3)
x1-2x2+2(1-x1-x2) >= 0
-x1-4x2 + 2 >= 0
x1 + 4x2 <= 2
y1 = 0, y2 = 5/6, y3 = 1/6
xB
C: continued...p2(x,c2)>=p2(x,c3)
3x1-2x2+0(
-[1x1+0x2-1(
x = axB+ (1-a)x-
0 <= a <=1}
2x1-2x2+1(1-x1-x2) >= 0
x1 - 3x2 + 1 >= 0
-x1 + 3x2 <= 1
C: continued...p2(x,c1)>=p2(x,c3)
2x1 + x2 = 1
x1 + 4x2 = 2
x1 = 2/7, x2 = 3/7, x3 = 2/7
x~= (2/7,3/7/2/7)
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