Find a value of k so that k= Find a value of k so that k || ekt is a solution to ' help (numbers) [-2]e = [1 ekt is a solution to a' x' = help (numbers) 7 2 -4 1 7 27 -4 1 18 ស x.
Find a value of k so that k= Find a value of k so that k || ekt is a solution to ' help (numbers) [-2]e = [1 ekt is a solution to a' x' = help (numbers) 7 2 -4 1 7 27 -4 1 18 ស x.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
7. Ordinary
![Find a value of \( k \) so that
\[
\begin{bmatrix}
1 \\
-1
\end{bmatrix}
e^{kt}
\]
is a solution to
\[
\vec{x}' =
\begin{bmatrix}
7 & 2 \\
-4 & 1
\end{bmatrix}
\vec{x}.
\]
\( k = \) [ ] help (numbers)
---
Find a value of \( k \) so that
\[
\begin{bmatrix}
1 \\
-2
\end{bmatrix}
e^{kt}
\]
is a solution to
\[
\vec{x}' =
\begin{bmatrix}
7 & 2 \\
-4 & 1
\end{bmatrix}
\vec{x}.
\]
\( k = \) [ ] help (numbers)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d6d6ec3-8d2a-4662-b20e-640089acaa34%2F7f069418-ecb5-4d19-af5c-d22c7487981b%2Fo7urile_processed.png&w=3840&q=75)
Transcribed Image Text:Find a value of \( k \) so that
\[
\begin{bmatrix}
1 \\
-1
\end{bmatrix}
e^{kt}
\]
is a solution to
\[
\vec{x}' =
\begin{bmatrix}
7 & 2 \\
-4 & 1
\end{bmatrix}
\vec{x}.
\]
\( k = \) [ ] help (numbers)
---
Find a value of \( k \) so that
\[
\begin{bmatrix}
1 \\
-2
\end{bmatrix}
e^{kt}
\]
is a solution to
\[
\vec{x}' =
\begin{bmatrix}
7 & 2 \\
-4 & 1
\end{bmatrix}
\vec{x}.
\]
\( k = \) [ ] help (numbers)
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