Find a three-digit positive integer such that the sum of all three digits is 14, the tens digit is two more than the ones digit, and if the digits are reversed, the number is unchanged.

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Q: The sum of two consecutive integers is 41. What are the integers?

A: Let the first integer = x Let the second integer = x +1

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A: Answer:   The five consecutive numbers are 10,11,12,13,14 whose sum is 60. i.e. 10+11+12+13+14 = 60

Q: 14 X-3 + 10 x + 6 =3

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