Find a sine equation having the following characteristics: Amplitude = 2 Period = 5 Horizontal Shift = - %3D 24 Vertical Shift = 3 y = [ ? ] sin([ ]x+ ) +[]

Q: Differentiate y = sin (x 2)

A:

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A: product rule: (uv)'= u'v+uv' Given: y=sinx tanx let u= sinx, v= tanx u'=(sinx)'=…

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A:

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A:

Q: The amplitude of y = } cos 3x is and the %3D period is .

A: Given: y=12cos3x To Find: Amplitude and Period Concept: if y=AcosBxthen Amplitude=Aand Period=2πB.

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A:

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A: Evaluate csc:1sin::sec:?

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A: Explanation of the answer is as follows

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A: that is equal to 0=sin(0-10) than 0=sin(-10) such that -10=sin^-1(0) that is equal to zero

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A:

Q: find sinA if hypotenuse = 2x and adjacent = x

A:

Q: COSX cosx 10. 1-sinx 1+sinx

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Q: What is the horizontal shift of the following equation? TT I+ cos 3x + O pi/2 units to the left…

A: y=Acos(Bx+C)+D  Where A is amplitude Period= 2π/B  Phase shift or horizontal shift = -C/B  Vertical…

Q: State the amplitude of the sinusoid A=-2/7 B=-5/7 x=b² sin(a²t - b)

A: Given: x=b2sina2t-b

Q: cos dx 5. Vaš sin² 3

A: Consider the integral: I=∫cos6x23dxx25sin23x23

Q: Verify: 1. (sinx – cosx)² – 1 = -sin2x %3D

A: We can verify the statement as below