Find a power series expansion about x = 0 for a general solution to the given differential equation. Your answer should include a general formula for the coefficients. ²z' + xz = 0 -z"
Find a power series expansion about x = 0 for a general solution to the given differential equation. Your answer should include a general formula for the coefficients. ²z' + xz = 0 -z"
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![Find a power series expansion about x = 0 for a general solution to the given differential equation. Your answer
should include a general formula for the coefficients.
-z" +x?z' + xz = 0
What is the power series solution to the differential equation?
2(-1)n (3-6.9...(3n))
(3n - 2)!
E (- 1)r (1 •4 •7.-(3n – 2))
(3n + 2)!
3n +
O A. Z(x) = ao 1+
+a, x+
Σ
n=1
n=1
(1.4.7..(3n - 2)) 3n
E (- 1)".
(2•5.8..(3n - 1)
E (- 1)"-
3n + 1
B. z(x) = ao 1+
+ a, x+
X-
(3n)!
(3n + 1)!
n=1
n=1
00
(3•6.9...(3n))
(1.4.7..(3n - 2)) 3n +
3n
OC. z(x) = ao 1+ E
+a, x+ E
(3n - 2)!
(3n + 2)!
n=1
n=1
(2.5.8.(3n - 1)) 3n + 1
Σ
(1.4.7...(3n - 2))
3n
D. z(x) = ao 1+ E
+
x+
(3n)!
(3n + 1
+ 1)!
n=1
n=1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8196164-f36a-4b0f-afd7-3e8c8a9d08cb%2F3030ca4b-aa89-4b91-8de2-cc07d2e1dbc6%2Ftzifb1p_processed.png&w=3840&q=75)
Transcribed Image Text:Find a power series expansion about x = 0 for a general solution to the given differential equation. Your answer
should include a general formula for the coefficients.
-z" +x?z' + xz = 0
What is the power series solution to the differential equation?
2(-1)n (3-6.9...(3n))
(3n - 2)!
E (- 1)r (1 •4 •7.-(3n – 2))
(3n + 2)!
3n +
O A. Z(x) = ao 1+
+a, x+
Σ
n=1
n=1
(1.4.7..(3n - 2)) 3n
E (- 1)".
(2•5.8..(3n - 1)
E (- 1)"-
3n + 1
B. z(x) = ao 1+
+ a, x+
X-
(3n)!
(3n + 1)!
n=1
n=1
00
(3•6.9...(3n))
(1.4.7..(3n - 2)) 3n +
3n
OC. z(x) = ao 1+ E
+a, x+ E
(3n - 2)!
(3n + 2)!
n=1
n=1
(2.5.8.(3n - 1)) 3n + 1
Σ
(1.4.7...(3n - 2))
3n
D. z(x) = ao 1+ E
+
x+
(3n)!
(3n + 1
+ 1)!
n=1
n=1
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