Find a polynomial function of degree 3 with -5, 0, and 1/2 as zeros f(x) = x³ + ²/1x² - 1/2x X f(x) = x³ + Of(x) = x³ I 2 502 5 x² - 1/x 2 52 2²/1x² + 1/{1x x ² − zx ²³ − xx = (x) ƒ O

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Find a polynomial function of degree 3 with -5, 0, and 1/2 as zeros
5
ƒ(x) = x³ + ²/1x² - 1/x
○
O
5
ƒ(x) = x³ + 1¹/21x² - 2x
f(x)= x³ - ²/3x² +/x
1/1
ƒ(x)
f(x)
8
=
x³
= x³ - 1²/1x² - 1/2 x
Transcribed Image Text:Find a polynomial function of degree 3 with -5, 0, and 1/2 as zeros 5 ƒ(x) = x³ + ²/1x² - 1/x ○ O 5 ƒ(x) = x³ + 1¹/21x² - 2x f(x)= x³ - ²/3x² +/x 1/1 ƒ(x) f(x) 8 = x³ = x³ - 1²/1x² - 1/2 x
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