Find a point P on the line and a vector v parallel to the line by inspection. Enter the vector i as i ,the vector jas i and the vector k as k .Enter vectors usingi, j, k notation. (a) (x, y) = (-5, 8) + 1 (2, 7) O P( – 5, 8) is on the line and v = 2i + 7j is parallel to the line. O P( - 5, 2) is on the line and v = 8i+ 7j is parallel to the line. O P(5, 2) is on the line and v = 8i + 7j is parallel to the line. O P(2, 7) is on the line and v = - 5i + 8j is parallel to the line. O P(5, 8) is on the line and v = 2i+ 7j is parallel to the line. eTextbook and Media (b) xi+ yj+ zk = (6i+3j – 4k) + 1(5j) %3D O P(6, 3, - 4) is on the line and v = 5j is parallel to the line. O P(6, 3, - 4) is on the line and v = 5i – 4k is parallel to the line. O P(6, 3, – 4) is on the line and v = 5i is parallel to the line. O P(6, 3, – 4) is on the line, and v = 5j – 4k is parallel to the line. O P(6, 3, – 4) is on the line and v = 5k is parallel to the line.
Find a point P on the line and a vector v parallel to the line by inspection. Enter the vector i as i ,the vector jas i and the vector k as k .Enter vectors usingi, j, k notation. (a) (x, y) = (-5, 8) + 1 (2, 7) O P( – 5, 8) is on the line and v = 2i + 7j is parallel to the line. O P( - 5, 2) is on the line and v = 8i+ 7j is parallel to the line. O P(5, 2) is on the line and v = 8i + 7j is parallel to the line. O P(2, 7) is on the line and v = - 5i + 8j is parallel to the line. O P(5, 8) is on the line and v = 2i+ 7j is parallel to the line. eTextbook and Media (b) xi+ yj+ zk = (6i+3j – 4k) + 1(5j) %3D O P(6, 3, - 4) is on the line and v = 5j is parallel to the line. O P(6, 3, - 4) is on the line and v = 5i – 4k is parallel to the line. O P(6, 3, – 4) is on the line and v = 5i is parallel to the line. O P(6, 3, – 4) is on the line, and v = 5j – 4k is parallel to the line. O P(6, 3, – 4) is on the line and v = 5k is parallel to the line.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.4: The Dot Product
Problem 46E
Related questions
Question
![Find a point P on the line and a vector v parallel to the line by inspection.
Enter the vector i as i ,the vector j as j and the vector k as k .Enter vectors using i, j, k notation.
(a) (x, y) = (-5, 8) + t (2, 7)
O P( – 5, 8) is on the line and v = 2i+ 7j is parallel to the line.
O P( – 5, 2) is on the line and v = 8i+ 7j is parallel to the line.
O P(5, 2) is on the line and v = 8i+ 7j is parallel to the line.
O P(2, 7) is on the line and v = - 5i+ 8j is parallel to the line.
O P(5, 8) is on the line and v = 2i+ 7j is parallel to the line.
eTextbook and Media
(b) xi+ yj + zk = (6i+ 3j – 4k) + 1(5j)
О Р(6, 3,
4) is on the line and v = 5j is parallel to the line.
O P(6, 3, - 4) is on the line and v = 5i – 4k is parallel to the line.
O P(6, 3, – 4) is on the line and v = 5i is parallel to the line.
О Р (6, 3,
-4) is on the line, and v
5j – 4k is parallel to the line.
O P(6, 3, – 4) is on the line and v = 5k is parallel to the line.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F955ba2c7-01b9-43a6-91ac-a1d2a78ed8ec%2Fff518e12-7f56-4cd2-b39d-732794ddd559%2Fftcv09_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find a point P on the line and a vector v parallel to the line by inspection.
Enter the vector i as i ,the vector j as j and the vector k as k .Enter vectors using i, j, k notation.
(a) (x, y) = (-5, 8) + t (2, 7)
O P( – 5, 8) is on the line and v = 2i+ 7j is parallel to the line.
O P( – 5, 2) is on the line and v = 8i+ 7j is parallel to the line.
O P(5, 2) is on the line and v = 8i+ 7j is parallel to the line.
O P(2, 7) is on the line and v = - 5i+ 8j is parallel to the line.
O P(5, 8) is on the line and v = 2i+ 7j is parallel to the line.
eTextbook and Media
(b) xi+ yj + zk = (6i+ 3j – 4k) + 1(5j)
О Р(6, 3,
4) is on the line and v = 5j is parallel to the line.
O P(6, 3, - 4) is on the line and v = 5i – 4k is parallel to the line.
O P(6, 3, – 4) is on the line and v = 5i is parallel to the line.
О Р (6, 3,
-4) is on the line, and v
5j – 4k is parallel to the line.
O P(6, 3, – 4) is on the line and v = 5k is parallel to the line.
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